[英]How to get the return value of a function passed to multiprocessing.Process?
[英]How to get function return value from a multiprocessing.Process?
我有两个功能,我想同时运行它们。 所以,我试过:
from multiprocessing import Process
def func1():
for i in range(0, 100000000):
pass
return 'abc'
def func2():
for i in range(0, 100000000):
pass
return 'xyz'
if __name__=='__main__':
p1 = Process(target=func1()).start()
p2 = Process(target=func2()).start()
现在,我怎样才能获得例如func1()
返回值?
我可以使用例如print(func1())
来获取返回值,但它再次执行该函数并且再次执行func1()
需要很长时间。 如何不让函数再次运行以获得结果?
这是我在评论中建议的如何使用multiprocessing.Pool
完成它。
import multiprocessing
def func1():
for i in range(0, 100000000):
pass
return 'abc'
def func2():
for i in range(0, 100000000):
pass
return 'xyz'
if __name__=='__main__':
funcs = func1, func2
with multiprocessing.Pool() as pool:
results = [pool.apply_async(func) for func in funcs]
pool.close()
pool.join()
results = [result.get() for result in results]
print(f'{results}') # -> ['abc', 'xyz']
您还可以使用concurrent.futures
模块
import concurrent.futures
_pool = concurrent.futures.ThreadPoolExecutor()
def func1():
for i in range(0, 100000000):
pass
return 'abc'
def func2():
for i in range(0, 100000000):
pass
return 'xyz'
if __name__=='__main__':
p1 = _pool.submit(func1)
p2 = _pool.submit(func2)
print(p1.result(), p2.result())
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.