cv2.Imshow() 在不同图像上显示相同的通道颜色

Question

我遇到了一个非常奇怪的问题。 Imshow() 为前三个 imshow 显示相同的图像 - 为什么？ （只有红色通道，它似乎已将蓝色和绿色归零）我正在创建原始图像的副本，但似乎这些操作会影响所有图像。 第四次 imshow 将红色通道显示为预期的灰度。 我究竟做错了什么？

    ##### Image processing ####
import cv2
import numpy as np
import matplotlib.pyplot as plt

img = cv2.imread('/home/pi/Documents/testcode_python/Tractor_actual/Pictures/result2.jpg') #reads as BGR
print(img.shape)

no_blue=img
no_green=img
only_red=img[:,:,2] #Takes only red channel from BGR image and saves to "only_red"

no_blue[:,:,0]=np.zeros([img.shape[0], img.shape[1]]) #Puts Zeros on Blue channels for "no_blue"
no_green[:,:,1]=np.zeros([img.shape[0], img.shape[1]])

print(no_blue.shape)

cv2.imshow('Original',img)
cv2.imshow('No Blue',no_blue)
cv2.imshow('No Green',no_green)
cv2.imshow('Only Red', only_red)
cv2.waitKey(0)
cv2.destroyAllWindows()

在此处输入图像描述

Answer 1

您需要创建图像的副本以避免使用与 img 相同的 memory 位置。 不确定这是否是您正在寻找的 only_red，但是将所有三个通道的蓝色和绿色设置为 0 可以避免将其视为单通道灰度图像。

    ##### Image processing ####
import cv2
import numpy as np
import matplotlib.pyplot as plt

img = cv2.imread('/home/pi/Documents/testcode_python/Tractor_actual/Pictures/result2.jpg') #reads as BGR
print(img.shape)

no_blue=img.copy() # copy of img to avoid using the same memory location as img
no_green=img.copy() # copy of img to avoid using the same memory location as img
only_red=img.copy() # similarly to above. 

# You also need all three channels of the RGB image to avoid it being interpreted as single channel image.
only_red[:,:,0] = np.zeros([img.shape[0], img.shape[1]])
only_red[:,:,1] = np.zeros([img.shape[0], img.shape[1]])
# Puts zeros for green and blue channels

no_blue[:,:,0]=np.zeros([img.shape[0], img.shape[1]]) #Puts Zeros on Blue channels for "no_blue"
no_green[:,:,1]=np.zeros([img.shape[0], img.shape[1]])

print(no_blue.shape)

cv2.imshow('Original',img)
cv2.imshow('No Blue',no_blue)
cv2.imshow('No Green',no_green)
cv2.imshow('Only Red', only_red)
cv2.waitKey(0)
cv2.destroyAllWindows()