从子数组中提取值并使用 jq 与上值合并为 csv

Question

我有一个带有子数组的 json 文件，我想在不同的行中获取具有相同 ID 的每个子数组。 json：

{
    "success": true,
    "status": {
        "http": {
            "code": 200,
            "message": "OK"
        }
    },
    "result": [{
        "id": "123456789",
        "start_date": "2021-01-01 08:17:39.989",
        "snippets": [{
            "transcript": "yes",
            "matched_entry": null,
            "start": "2021-01-16 11:32:25.922"
        }, {
            "transcript": null,
            "matched_entry": null,
            "start": "2021-01-16 11:32:38.179"
        }]
    }, {
        "id": "987654321",
        "start_date": "2021-01-01 08:17:39.989",
        "duration_total": 301,
        "snippets": [{
            "transcript": "yes",
            "matched_entry": null,
            "start": "2021-01-01 08:17:54.055"
        }, {
            "transcript": "something",
            "matched_entry": " meta entry",
            "start": "2021-01-01 08:18:11.028"
        }, {
            "transcript": "no",
            "matched_entry": null,
            "start": "2021-01-01 08:18:24.057"
        }]
    }]
}

我试图得到：

123456789, yes , null, "2021-01-16 11:32:25.922"
123456789, null, null, "2021-01-16 11:32:38.179"
987654321, yes, null, "2021-01-01 08:17:54.055"
987654321, something, "meta entry", "2021-01-01 08:18:11.028"
987654321, no, null, "2021-01-01 08:18:24.057"

第一次尝试是：

jq -rc ".result[] | {id: .id, snippetsTranscript: .snippets[].transcript, snippetsMatchedEntry: .snippets[].matched_entry, snippetsStart: .snippets[].start}" 210101_210121_copy.json

但结果是返回了每个组合：

{"id":"123456789","snippetsTranscript":"yes","snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:25.922"}
{"id":"123456789","snippetsTranscript":"yes","snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:38.179"}
{"id":"123456789","snippetsTranscript":"yes","snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:25.922"}
{"id":"123456789","snippetsTranscript":"yes","snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:38.179"}
{"id":"123456789","snippetsTranscript":null,"snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:25.922"}
{"id":"123456789","snippetsTranscript":null,"snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:38.179"}
{"id":"123456789","snippetsTranscript":null,"snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:25.922"}
{"id":"123456789","snippetsTranscript":null,"snippetsMatchedEntry":null,"snippetsStart":"2021-01-16 11:32:38.179"} ...

第二次尝试是：

jq -rc ".result[] | {id: .id, snippetsMatchedEntry: [.snippets[].matched_entry], snippetsStart: [.snippets[].start], snippetsTranscript: [.snippets[].transcript]}" 210901_210921_copy.json

但结果是：

{"id":"123456789","snippetsMatchedEntry":[null,null],"snippetsStart":["2021-01-16 11:32:25.922","2021-01-16 11:32:38.179"],"snippetsTranscript":["yes",null]}
{"id":"987654321","snippetsMatchedEntry":[null," meta entry",null],"snippetsStart":["2021-01-01 08:17:54.055","2021-01-01 08:18:11.028","2021-01-01 08:18:24.057"],"snippetsTranscript":["yes","something","no"]}

jq可以吗？

Answer 1

对于result数组的每个元素，创建一个仅包含id字段的 object，并为snippets子数组的每个元素添加它：

.result[] | {id} + .snippets[]

如果您不需要snippets数组的所有字段，只需像以前一样声明它们

.result[] | {id} + (.snippets[] | {transcipt, matched_entry, start})

在jqplay.org上试试