[英]How do I detect only the black rectangle that appears in the reference image with OpenCV
我只需要检测出现在那里的矩形,但由于某种原因它没有检测到它,但它确实检测到了许多其他小人仔
import cv2
img=cv2.imread('vision.png') #read image
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
Blur=cv2.GaussianBlur(gray,(5,5),1) #apply blur to roi
Canny=cv2.Canny(Blur,10,50) #apply canny to roi
#Find my contours
contours =cv2.findContours(Canny,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_NONE)[0]
cntrRect = []
for i in contours:
epsilon = 0.05*cv2.arcLength(i,True)
approx = cv2.approxPolyDP(i,epsilon,True)
if len(approx) == 4:
cv2.drawContours(img,cntrRect,-1,(0,255,0),2)
cv2.imshow('Image Rect ONLY',img)
cntrRect.append(approx)
cv2.waitKey(0)
cv2.destroyAllWindows()
如何仅检测图像中出现的黑色矩形
但是这段代码检测到更多的矩形,我不想要 whis,但我只想检测黑色的 countour 矩形
原始图像
这是在 Python/OpenCV 中执行此操作的一种方法。
阈值图像。 然后使用形态学来填充矩形。 然后得到最大的轮廓并在输入上绘制。
输入:
import cv2
import numpy as np
# load image
img = cv2.imread("black_rectangle_outline.png")
# convert to grayscale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# threshold
thresh = cv2.threshold(gray, 30, 255, cv2.THRESH_BINARY)[1]
# apply close morphology
kernel = np.ones((111,111), np.uint8)
morph = cv2.morphologyEx(thresh, cv2.MORPH_OPEN, kernel)
# invert so rectangle is white
morph = 255 - morph
# get largest contour and draw on copy of input
result = img.copy()
contours = cv2.findContours(morph, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
contours = contours[0] if len(contours) == 2 else contours[1]
big_contour = max(contours, key=cv2.contourArea)
cv2.drawContours(result, [big_contour], 0, (255,255,255), 1)
# write result to disk
cv2.imwrite("black_rectangle_outline_thresh.png", thresh)
cv2.imwrite("black_rectangle_outline_morph.png", morph)
cv2.imwrite("black_rectangle_outline_result.png", result)
# display results
cv2.imshow("THRESH", thresh)
cv2.imshow("MORPH", morph)
cv2.imshow("RESULT", result)
cv2.waitKey(0)
cv2.destroyAllWindows()
阈值图像:
形态图像:
结果:
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