当产生 15 个球时，第 15 次点击后游戏停止反应

Question

此游戏将在每次点击后在网格上的随机位置生成一个球。

问题

但它在达到 15 个球后停止对进一步点击做出反应（见上面的截图）。

Pygame代码

import pygame
from random import randint

pygame.init()
gameDisplay = pygame.display.set_mode((915,915))
colors = [(102,51,0),(0,255,255),(0,255,0),(0,51,204),(102,0,204),(255,255,0),(255,0,0)]
slots = []
x = 0
y = 0
click_pos = (0,0)
play = True
#Size of squares
size = 83
white = (255,255,255)
gray = (200,200,200)
deep_gray = (20,20,20)
green = (0,255,0)
black = (0,0,0)
boardLength = 9
z = 0
clicked = False
selecting = False
ball_spawn = False
balls_x = []
balls_y = []
ball_amount = 0
ball_color = []
ball_drew = 0
get_ball_pos = False
click_once = 0
#bg color
gameDisplay.fill(deep_gray)

# GRID
while boardLength > z:
    #border
    pygame.draw.rect(gameDisplay, black, [size-5,size-5,boardLength*size+5 ,boardLength*size+5])
    #grid squares
    for i in range(1,boardLength+1):
        for z in range(1,boardLength+1):
            pygame.draw.rect(gameDisplay, gray, [size*z,size*i,size-5,size-5])

# GAME
while play == True:
    for events in pygame.event.get():
        if events.type == pygame.MOUSEBUTTONUP:
            click_pos = list(pygame.mouse.get_pos())
            clicked = True
        if events.type == pygame.QUIT:
            play = False
    #get click pos on grid
    if clicked == True:
        click_once += 1
        if click_once == 1:
            x = round((click_pos[0]-size/2) / size)
            y = round((click_pos[1]-size/2) / size)
            if x > 0 and x < 10 and y > 0 and y < 10:
                grid_x = x*size
                grid_y = y*size
            clicked = False
            selecting = True
            get_ball_pos = True
            ball_spawn = True
    else:
        click_once = 0
    #selector
    if selecting:
        pygame.draw.rect(gameDisplay, green, (grid_x,grid_y,size-5,size-5), 5)

    # BALLS
    while ball_spawn:
        while get_ball_pos:
            ball_grid_x = randint(1,9)
            ball_grid_y = randint(1,9)
            if not (ball_grid_x in balls_x and ball_grid_y in balls_y):
                get_ball_pos = False
                balls_x.append(ball_grid_x)
                balls_y.append(ball_grid_y)
                ball_color.append(colors[randint(0,6)])
                ball_amount += 1
        while ball_drew < ball_amount:
            pygame.draw.circle(gameDisplay, ball_color[ball_drew], (balls_x[ball_drew]*size + size*0.5 - 2, balls_y[ball_drew]*size + size*0.5 - 2), 25)
            pygame.draw.circle(gameDisplay, black, (balls_x[ball_drew]*size + size*0.5 - 2, balls_y[ball_drew]*size + size*0.5 - 2), 25, 5)
            ball_drew += 1
        ball_drew = 0
        ball_spawn = False
    #final result
    pygame.display.update()

pygame.quit()
quit()

中断后的堆栈跟踪

由于程序不再对点击做出反应，我在控制台中使用 CTRL + C 中断了它。 中断执行后，控制台显示如下：

pygame 2.0.1 (SDL 2.0.14, Python 3.6.9)
Hello from the pygame community. https://www.pygame.org/contribute.html
^CTraceback (most recent call last):
  File "SO_pygame.py", line 73, in <module>
    ball_grid_x = randint(1,9)
  File "/usr/lib/python3.6/random.py", line 221, in randint
    return self.randrange(a, b+1)
  File "/usr/lib/python3.6/random.py", line 192, in randrange
    istop = _int(stop)
KeyboardInterrupt

我怎样才能解决这个问题？

Answer 1

问题是条件：

 if not (ball_grid_x in balls_x and ball_grid_y in balls_y):

此条件检查ball_grid_x行中是否有球以及ball_grid_y列中是否有球。 然而，这些可以是不同的球。 因此，如果每一行都有一个球，每一列都有一个球，那么这个条件会创建一个无限循环：

您需要测试 positionv (ball_grid_x, ball_grid_y)是否有球：

if not (ball_grid_x, ball_grid_y) in zip(balls_x, balls_y):