[英]Fill Dataframe with values from another Dataframe (not the same column names)
我正在尝试用另一个 dataframe (InputData) 中的值填充 Python 中的空 dataframe (OutputData)。
InputData 有四列(“Strike”、“DTE”、“IV”、“Pred_IV”)OutputData 具有来自 InputData 的所有唯一 Strikes 作为索引,并且作为列名称,所有来自 Input Data 的唯一 DTE。
我的目标是用来自 InputData 的相应“Pred_IV”值填充 OutputData。 因为它需要同时匹配索引和列名,所以我没有考虑如何使用任何已知的 function 进行匹配。
如果 InputData 中没有与索引和列名匹配的值,则该值可以保持为 NaN
在下面找到我使用 df.to_dict() 提取的数据帧以获取更多详细信息。
非常感谢您的帮助。
最好的,弗洛
输入数据.head()
Strike DTE IV Pred_IV
8 0.5131 2.784 0.3366 0.733360
9 0.5131 3.781 0.3291 0.735295
20 0.5864 2.784 0.3178 0.733476
21 0.5864 3.781 0.3129 0.735357
22 0.5864 4.778 0.3008 0.736143
InputData.head().to_dict()
{'Strike': {8: 0.5131, 9: 0.5131, 20: 0.5864, 21: 0.5864, 22: 0.5864},
'DTE': {8: 2.784, 9: 3.781, 20: 2.784, 21: 3.781, 22: 4.778},
'IV': {8: 0.33659999999999995,
9: 0.32909999999999995,
20: 0.3178,
21: 0.3129,
22: 0.30079999999999996},
'Pred_IV': {8: 0.7333602770095773,
9: 0.7352946387206533,
20: 0.7334762408944806,
21: 0.7353567361456718,
22: 0.7361431377881676}})
输出数据.head()
0.025 0.101 0.197 0.274 0.523 0.772 1.769 2.267 2.784 3.781 4.778 5.774
0.5131 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
0.5864 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
0.6597 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
0.7330 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
0.7697 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
OutputData.head(2).to_dict()
{0.025: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
0.101: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
0.197: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
0.274: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
0.523: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
0.772: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
1.769: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
2.267: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
2.784: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
3.781: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
4.778: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan},
5.774: {0.5131: nan,
0.5864: nan,
0.6597: nan,
0.733: nan,
0.7696999999999999: nan}}
这是一种方法来做我认为你的问题是问:
import pandas as pd
import numpy as np
InputData = pd.DataFrame(
columns='Strike,DTE,IV,Pred_IV'.split(','),
index=[8,9,20,21,22],
data=[[0.5131, 2.784, 0.3366, 0.733360],
[0.5131, 3.781, 0.3291, 0.735295],
[0.5864, 2.784, 0.3178, 0.733476],
[0.5864, 3.781, 0.3129, 0.735357],
[0.5864, 4.778, 0.3008, 0.736143]])
OutputData = pd.DataFrame(data=np.NaN,
columns=pd.Index(name='DTE', data=list(set(InputData.DTE.to_list()))),
index=pd.Index(name='Strike', data=list(set(InputData.Strike.to_list()))))
def foo(x):
OutputData.loc[x.Strike, x.DTE] = x.Pred_IV
InputData.apply(foo, axis=1)
print(OutputData)
Output:
DTE 2.784 3.781 4.778
Strike
0.5131 0.733360 0.735295 NaN
0.5864 0.733476 0.735357 0.736143
如果你更喜欢未命名的索引,你可以这样做:
OutputData = pd.DataFrame(data=np.NaN,
columns=list(set(InputData.DTE.to_list())),
index=list(set(InputData.Strike.to_list())))
Output:
2.784 3.781 4.778
0.5131 0.733360 0.735295 NaN
0.5864 0.733476 0.735357 0.736143
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