使用 in 运算符验证 Python 列表中存在的值

Question

我在下面编写了简单的代码来检查 Python 列表（unique_status）中存在的值：

if "Match" in unique_status and "Mismatch" in unique_status:
    print("Match and Mismatch both found.")
elif "Match" in unique_status:
    print("Only Match found.")
elif "Mismatch" in unique_status:
    print("Only Mismatch found.")
else:
    print("Something else is also present.)

For Value in Unique_Status = ['Match'], I am getting "Only Match Found"
For Value in Unique_Status = ['Mismatch'], I am getting "Only Mismatch Found"
For Value in Unique_Status = ['Match','Mismatch'], I am getting "Match and Mismatch both found."

但是，当列表还包含一些其他值时，例如 ['Match','Mismatch','XYZ']，则其他部分不会被执行。 我的代码需要什么条件/修改才能检查 Unique_Status 列表，并执行 else 条件，以防除 Match 和 Mismatch 之外还存在其他一些值。

Answer 1

if "Match" in unique_status and "Mismatch" in unique_status:
    print("Match and Mismatch both found.")
elif "Match" in unique_status:
    print("Only Match found.")
elif "Mismatch" in unique_status:
    print("Only Mismatch found.")

if any( word not in ['Match','Mismatch'] for word in unique_status ):
    print("Something else is also present.)

跟进

如果你只想打印一件东西，你应该这么说。 在这种情况下，“in”显然是错误的运算符。 你需要寻找平等：

if unique_status == ["Match"]:
    print("Only Match found.")
elif unique_status == ["Mismatch"]:
    print("Only Mismatch found.")
elif set(unique_status) == set(["Match","Mismatch"]):
    print("Match and Mismatch both found.")
else:
    print("Something else is also present.)

Answer 2

因为如果unique_status = ['Match','Mismatch','XYZ']您的第一个if 条件得到满足因此，else 不起作用