需要上个月的数据，加上上个月的 10 天数据和当月的 3 天数据

Question

我想从 4 月 1 日到 4 月 30 日提取上个月的数据。 但还需要上个月的 10 天数据（3 月 21 日之后的任何数据）和当月 3 天的数据（5 月 1 日 - 5 月 3 日）。 我编写了以下代码，它将提取 4 月份的数据，但正在努力提取 3 月和 5 月的数据。 这是每月的脚本，所以想写一个代码，它会查看当前月份，然后根据上面提到的逻辑检索数据。

有人可以指导我吗？

import datetime
df["Sent_Date"] = pd.to_datetime(df["Sent_Date"])

from datetime import date, timedelta
#strategy_assignemnt.info()
#Create a last_day_of_the_previous_month variable which will read the system date, then  replace it with the day 1 of the current month and set the timedelta which will consider the last month of the last date
last_day_of_the_previous_month = date.today().replace(day = 1)- timedelta(days= 1)
#Create a first_day_of_the_previous_month variable which will read the system date, then  replace it with the day 1 of the current month and set the timedelta which will consider the last month of the last date
first_day_of_the_previous_month = date.today().replace(day = 1) - timedelta(last_day_of_the_previous_month.day)
first_day_of_the_previous_month = pd.to_datetime(first_day_of_the_previous_month).strftime ('%Y-%m-%d')
last_day_of_the_previous_month = pd.to_datetime(last_day_of_the_previous_month).strftime ('%Y-%m-%d')

Answer 1

使用相同的计算来获得上个月前 10 天和当前月 3 天

import datetime
from datetime import date, timedelta

prev_month_last = date.today().replace(day=1) - timedelta(days=1)
prev_month_first = prev_month_last.replace(day=1)
prev_month_prev_10days_start = prev_month_first - timedelta(days=10)
prev_month_prev_10days_end = prev_month_first - timedelta(days=1)
curr_month_3days_start = date.today().replace(day=1)
curr_month_3days_end = curr_month_3days_start + timedelta(days=2)

print(f'Previous month start date: {prev_month_first} & end {prev_month_last}')
print(f'Ten days before previous month start date: {prev_month_prev_10days_start} & end {prev_month_prev_10days_end}')
print(f'Current month 3days start {curr_month_3days_start} & end {curr_month_3days_end}')