获取属性错误：__enter__ 错误

Question

好的，我得到属性错误：输入语句。 试图让python检查下周一的日期，如果有该日期向前移动，那么如果将其更改为星期二，那么如果没有打印出错误：下周没有开始......但是虽然得到了那个错误并且不能想办法。

import os
import pandas as pd
import datetime as DT
from dateutil.relativedelta import relativedelta, MO, TU

hr_file = "Upcoming Hires.xlsx"
with pd.read_excel(hr_file, sheet_name="New Hires",parse_dates=["Start Date"]) as reader:
    
    now = now = DT.datetime.now()
    nm = now - relativedelta(weekday=MO(+1))
    next_monday = now - relativedelta(weekday=MO(+1))

    if next_monday in reader:
        print("true")
    if not next_monday in reader:
        nm = now - relativedelta(weekday=TU(+2))
        next_monday = nm.strftime("%#m/%#d/%#y")
        if next_monday in reader:
            print("had to move the date for the start date to tuesday but it True")
        if not next_monday in reader:
            print("error: there is no starter next week...")

得到这个错误

AttributeError                            Traceback (most recent call last)
c:\masterscript\test.py in <cell line: 1>()
----> 7 with pd.read_excel(hr_file, sheet_name="New Hires",parse_dates=["Start Date"]) as reader:
      8     now = now = DT.datetime.now()
      9     nm = now - relativedelta(weekday=MO(+1))

AttributeError: __enter__

Answer 1

您不需要上下文管理器来使用pd.read_excel ，因为此函数从文档返回 DataFrame 或 DataFrame 的字典：

返回： DataFrame 或 DataFrames 的字典
来自传入的 Excel 文件的 DataFrame。 有关何时返回 DataFrames 的字典的更多信息，请参阅 sheet_name 参数中的注释。

import pandas as pd
import numpy as np

with pd.DataFrame(np.random.rand(5,10)) as reader:
    print(reader)

AttributeError                            Traceback (most recent call last)
----> 1 with pd.DataFrame(np.random.rand(5,10)) as reader:
      2     print(reader)
AttributeError: __enter__

您可以将pd.read_excel的返回值分配给一个变量，并将reader调整到包含您需要的日期的列。 类似于以下内容：

...
hr_file = "Upcoming Hires.xlsx"
df = pd.read_excel(hr_file, sheet_name="New Hires",parse_dates=["Start Date"])

now = now = DT.datetime.now()
nm = now - relativedelta(weekday=MO(+1))
next_monday = now - relativedelta(weekday=MO(+1))

if next_monday in df['Start Date']:
    print("true")
if not next_monday in df['Start Date']:
...
...