[英]Pyspark, writing a loop to create multiple new columns based on different conditions
假设我有一个 Pyspark DataFrame 具有以下列:
用户、分数、国家、风险/安全、payment_id
我列出了阈值:[10,20,30]
现在我想为每个阈值创建一个新列:
两者都应按国家/地区分组。
结果应该是这样的:
Country | % payments thresh 10 | % users thresh 10 | % payments thresh 20 ...
A
B
C
我能够使其与外部 for 循环一起工作,但我希望它全部在一个 dataframe 中。
thresholds = [10, 20, 30]
for thresh in thresholds:
df = (df
.select('country', 'risk/safe', 'user', 'payment')
.where(F.col('risk\safe') == 'risk')
.groupBy('country').agg(F.sum(F.when(
(F.col('score') >= thresh),1
)) / F.count('country').alias('% payments'))
在agg()
中使用列表推导。
pay_aggs = [(func.sum((func.col('score')>=thresh).cast('int'))/func.count('country')).alias('% pay '+str(thresh)) for thresh in thresholds]
user_aggs = [(func.countDistinct(func.when(func.col('score')>=thresh, func.col('user')))/func.countDistinct('user')).alias('% user '+str(thresh)) for thresh in thresholds]
df. \
select('country', 'risk/safe', 'user', 'payment'). \
where(func.col('risk\safe') == 'risk'). \
groupBy('country'). \
agg(*pay_aggs, *user_aggs)
pay_aggs
列表将生成以下聚合(您可以轻松打印列表)
# [Column<'(sum(CAST((score >= 10) AS INT)) / count(country)) AS `% pay 10`'>,
# Column<'(sum(CAST((score >= 20) AS INT)) / count(country)) AS `% pay 20`'>,
# Column<'(sum(CAST((score >= 30) AS INT)) / count(country)) AS `% pay 30`'>]
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