我怎样才能得到与个位数一致的两位数的数字坐标列的最后一位

Question

单独的文本文件中有一个网格，function 读取该文件并返回一个 object，其中包含逐行读取文本文件的网格

我的问题是在我的数字坐标中，单个数字与双位数的最后一位数字不对齐

def load_board(filename):
    result = "  "
    with open(filename) as f:
        print(f)
        for index, line in enumerate(f):
            if index == 0:
                result += ' '+' '.join([chr(alphabets + 65) for alphabets in range(len(line) - 1)]) + '\n' #the alphabetical column heading

            result += f"{-(index + 1)+(20)}"
            if (len(result))<2:
                 result+=' '.join(result)
       
            for characters in line:
                result += " " + (characters)
        return result

def save_board(filename, board):
    with open(filename, "wt") as f:
        f.write(board)

b = load_board("l19.txt")
print(b)
save_board("l19b.txt", b)

这给了我 output 的

   A B C D E F G H I J K L M N O P Q R S
19 . . . . @ @ @ . O O . . @ . O O O . O 
18 @ O O @ O @ . . @ O @ O . . . @ @ . @ 
17 @ O . . @ O . O O O O O . O O O O O @ 
16 . . @ @ . O O . @ . . O @ O . @ . O . 
15 O . @ . @ . O @ . O O @ @ O . . O @ O 
14 O . . . O O O @ . @ @ . . . @ . O @ @ 
13 . . @ O @ . . @ . . O O O . @ . @ . . 
12 . . @ @ . @ @ @ . . . @ O . O . . . @ 
11 @ O . . @ . @ @ @ @ O . . @ O O O @ O 
10 @ . . O . @ @ O @ O O @ @ . @ . O @ . 
9 @ O O O . . @ O . . @ @ O @ @ @ . O O 
8 @ @ O @ . O O O . @ . O @ . @ @ @ . @ 
7 @ . O . O @ O O . O O . @ O @ . . @ O 
6 @ . . . O @ @ O O @ . @ @ . . O . O . 
5 O O @ @ . . O @ @ . @ . @ . O @ @ O . 
4 @ . O . . O O . @ O @ O @ O O . @ @ . 
3 @ @ O O @ . O . @ . O @ . @ O @ O . . 
2 . . . O O @ @ O . @ O . O . @ O O @ . 
1 @ @ . @ O . @ @ . . @ O O O O O @ @ @

我试图通过添加一个条件语句来使其对齐，该条件语句声明如果数字的长度小于 2 以添加空格但是它不起作用

Answer 1

使用 f-string 的选项格式化为 2 长度值，因此您可以删除无用的if (len(result))<2:块

您还可以使用string.ascii_uppercase进行简化

from string import ascii_uppercase

def load_board(filename):
    result = "  "
    with open(filename) as f:
        for index, line in enumerate(f):
            # the alphabetical column heading
            if index == 0:
                result += ' ' + ' '.join(ascii_uppercase[:len(line) - 1]) + '\n'
            # the number prefix
            result += f"{19 - index:2d}"
            # the chars
            result += ' ' + ' '.join(line.strip()) + '\n'
    return result