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[英]return variable name from outside of function, as string inside python function
[英]How to print the function name as a string in Python from inside that function
def applejuice(q):
print THE FUNCTION NAME!
它应该导致“applejuice”作为一个字符串。
这也有效:
import sys
def applejuice(q):
func_name = sys._getframe().f_code.co_name
print func_name
def applejuice(**args):
print "Running the function 'applejuice'"
pass
或使用:
myfunc.__name__
>>> print applejuice.__name__
'applejuice'
import traceback
def applejuice(q):
stack = traceback.extract_stack()
(filename, line, procname, text) = stack[-1]
print procname
我假设这用于调试,因此您可能希望查看traceback
模块提供的其他过程。 它们可以让你打印整个调用堆栈,异常跟踪等。
其他方式
import inspect
def applejuice(q):
print inspect.getframeinfo(inspect.currentframe())[2]
你需要解释你的问题是什么。 因为你的问题的答案是:
print "applejuice"
这个网站给了我一个很好的解释,说明sys._getframe.f_code.co_name如何工作,返回函数名称。
http://code.activestate.com/recipes/66062-determining-current-function-name/
def foo():
# a func can just make a call to itself and fetch the name
funcName = foo.__name__
# print it
print 'Internal: {0}'.format(funcName)
# return it
return funcName
# you can fetch the name externally
fooName = foo.__name__
print 'The name of {0} as fetched: {0}'.format(fooName)
# print what name foo returned in this example
whatIsTheName = foo()
print 'The name foo returned is: {0}'.format(whatIsTheName)
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