How to print the function name as a string in Python from inside that function

Question

def applejuice(q):
   print THE FUNCTION NAME!

It should result in "applejuice" as a string.

Answer 1

This also works:

import sys

def applejuice(q):
    func_name = sys._getframe().f_code.co_name
    print func_name

Answer 2

def applejuice(**args):
    print "Running the function 'applejuice'"
    pass

or use:

myfunc.__name__

>>> print applejuice.__name__
'applejuice'

Also, see how-to-get-the-function-name-as-string-in-python

Answer 3

import traceback

def applejuice(q):
   stack = traceback.extract_stack()
   (filename, line, procname, text) = stack[-1]
   print procname

I assume this is used for debugging, so you might want to look into the other procedures offered by the traceback module . They'll let you print the entire call stack, exception traces, etc.

Answer 4

Another way

import inspect 
def applejuice(q):
    print inspect.getframeinfo(inspect.currentframe())[2]

Answer 5

You need to explain what your problem is. Because the answer to your question is:

print "applejuice"

Answer 6

This site gave me a decent explanation of how sys._getframe.f_code.co_name works that returns the function name.

http://code.activestate.com/recipes/66062-determining-current-function-name/

Answer 7

def foo():
    # a func can just make a call to itself and fetch the name
    funcName = foo.__name__
    # print it
    print 'Internal: {0}'.format(funcName)
    # return it
    return funcName

# you can fetch the name externally
fooName = foo.__name__
print 'The name of {0} as fetched: {0}'.format(fooName)

# print what name foo returned in this example
whatIsTheName = foo()
print 'The name foo returned is: {0}'.format(whatIsTheName)