2D數組無法解析為變量

Question

我正在從事另一項家庭作業，而我一直陷入這個問題。 我的2D int [] [] graph1（數組）“無法解析為變量”？

基本上，我將一些圖形轉換為2D數組，必須將它們上載到程序中，如果它們是PATH或CIRCUIT，則將讀取它們。 一個是有向圖，另一個（我現在在說）是無向的。

這是我到目前為止的內容：

boolean undirectedCircuit (int [][] graph)
{
    //graph = graph1(graph1(null));

    int edgeCounter = 0;

    for (int edge = 0; edge < graph.length; edge++)
    {
        /* SET FOR WHEN 1s are found in array: edgeCounter++;*/
        if(graph[4][4] == '1')
        {
            edgeCounter++;
            System.out.println("edgeCounter found '1' " + edgeCounter + "times");
        }
    }

    if (edgeCounter % 2 == 0)
    {
        System.out.println("This is a circuit!");
        //return true;
    }
    else System.out.println("This is not a circuit!!");
    return false;
    }

public void go ()
{
    graph1 = new int[][] //This line is complained about.
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

    undirectedCircuit(graph1); //This is complained about.
} 

任何建議都很好！

Answer 1

graph1（數組）“無法解析為變量

您尚未聲明graph1 ，因此編譯器無法解析符號graph1 。

解：-

graph1 = new int[][] //This line is complained about.
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

應該

int[][] graph1 = 
            {
            {0,1,1,1,0},
            {1,0,0,0,1},
            {1,0,0,1,0},
            {1,0,1,0,1},
            {0,1,0,1,0}
            };

Answer 2

您從未聲明graph1 。

您應該將graph1 = new int[][] ...更改為int[][] graph1 = new int[][] ...