[英]Subsetting and counting values in columns in a data.frame
我有一個長度為100000的data.frame。現在,我想計算該子集中正負值的不同data.frame長度(水平在0.01到0.99之間)。
> dput(sumDF[1:100])
structure(c(3000, 2000, 5000, 4000, 1000, 4000, 0, 3000, 4000,
2000, 2000, 3000, 1000, -3000, 2000, 0, 4000, 1000, 1000, 2000,
2000, 2000, 2000, 1000, 3000, 1000, 4000, 3000, 2000, 3000, 1000,
1000, 4000, 2000, 0, 1000, 2000, 5000, 3000, 3000, 0, 2000, 2000,
3000, 1000, -1000, 2000, 1000, 2000, 3000, 2000, 3000, 2000,
2000, 2000, 2000, 3000, 3000, 3000, 2000, 3000, 3000, 1000, 3000,
1000, 2000, 1000, -1000, 0, 2000, 2000, 3000, 0, 3000, 2000,
2000, 5000, 3000, 2000, 1000, 3000, 3000, 4000, 1000, 2000, 2000,
3000, 0, 3000, 1000, 0, 4000, 4000, 2000, 3000, 0, 2000, 4000,
0, 0), .Names = c("modelOutcome1", "modelOutcome2", "modelOutcome3",
"modelOutcome4", "modelOutcome5", "modelOutcome6", "modelOutcome7",
"modelOutcome8", "modelOutcome9", "modelOutcome10", "modelOutcome11",
"modelOutcome12", "modelOutcome13", "modelOutcome14", "modelOutcome15",
"modelOutcome16", "modelOutcome17", "modelOutcome18", "modelOutcome19",
"modelOutcome20", "modelOutcome21", "modelOutcome22", "modelOutcome23",
"modelOutcome24", "modelOutcome25", "modelOutcome26", "modelOutcome27",
"modelOutcome28", "modelOutcome29", "modelOutcome30", "modelOutcome31",
"modelOutcome32", "modelOutcome33", "modelOutcome34", "modelOutcome35",
"modelOutcome36", "modelOutcome37", "modelOutcome38", "modelOutcome39",
"modelOutcome40", "modelOutcome41", "modelOutcome42", "modelOutcome43",
"modelOutcome44", "modelOutcome45", "modelOutcome46", "modelOutcome47",
"modelOutcome48", "modelOutcome49", "modelOutcome50", "modelOutcome51",
"modelOutcome52", "modelOutcome53", "modelOutcome54", "modelOutcome55",
"modelOutcome56", "modelOutcome57", "modelOutcome58", "modelOutcome59",
"modelOutcome60", "modelOutcome61", "modelOutcome62", "modelOutcome63",
"modelOutcome64", "modelOutcome65", "modelOutcome66", "modelOutcome67",
"modelOutcome68", "modelOutcome69", "modelOutcome70", "modelOutcome71",
"modelOutcome72", "modelOutcome73", "modelOutcome74", "modelOutcome75",
"modelOutcome76", "modelOutcome77", "modelOutcome78", "modelOutcome79",
"modelOutcome80", "modelOutcome81", "modelOutcome82", "modelOutcome83",
"modelOutcome84", "modelOutcome85", "modelOutcome86", "modelOutcome87",
"modelOutcome88", "modelOutcome89", "modelOutcome90", "modelOutcome91",
"modelOutcome92", "modelOutcome93", "modelOutcome94", "modelOutcome95",
"modelOutcome96", "modelOutcome97", "modelOutcome98", "modelOutcome99",
"modelOutcome100"))
> levels <- c(0.01, 0.05, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 0.95, 0.99)
> levelLength <- length(sumDF) * levels
> levelLength
[1] 1000 5000 10000 20000 30000 40000 50000 60000 70000 80000 90000 95000 99000
我的問題是我得到了“ data.frame”應該多長時間,但是我沒有得到data.frame中“獲勝者”和“失敗者”的數目。 因此,一維data.frame的值大於0(獲勝者),或者小於或等於0(失敗者)。
為了舉例說明,我的data.frame的長度為100000
。 在1%的水平上,它的長度只有1000
。 例如,從這1000個元素中,是800高於0,200低於或等於0。如何獲得800
和200
?
我嘗試了以下方法:
countWin <- length(sumDF[1:levelLength > 0])
Warning message:
In 1:levelLength : numerical expression has 13 elements: only the first used
有什么建議,如何從向量中僅獲取一定數量的元素?
感謝您的答復。
更新
例:
我的data.frame sumDF看起來像這樣:
> sumDF[1:3]
modelOutcome1 modelOutcome2 modelOutcome3
3000 2000 5000
我的data.frame sumDF的長度為100000
我想用以下級別長度將我的data.frame sumDF子集化。
> levelLength
[1] 1000 5000 10000 20000 30000 40000 50000 60000 70000 80000 90000 95000 99000
因此,對於levelLength 1000,我想將sumDF從0子集到1000。
此外,在這個子集中,我想計算所有val >0
,我的贏家,所有<=0
,我的輸家。
我的最終data.frame應該看起來像這樣:
"levels" "winners" "losers"
0.01 900 100
0.05 2400 2600
0.10 6000 4000
0.20 . .
0.30 . .
0.40
0.50
0.60
0.70
0.80
0.90
0.95
0.99
dput
輸出是一個vector
。 要獲得小於0的值之sum
,
sum(sumDF<0)
#[1] 3
我們還可以使用table
來獲得失敗者和獲勝者的頻率
table(sumDF <0)
#FALSE TRUE
# 97 3
如果我們有一個data.frame
或matrix
colSums(sumDF <0)
不確定我是否了解最近的編輯,也許在cut
對象切成不同的容器后,我們會得到'sumDF'的頻率。 使用cut
,我們可以通過指定breaks
來獲得這些組。
levellength <- c(1, 5, seq(10, 90, by=10), 95, 99)
tbl <- table(cut(sumDF, breaks=levellength), sumDF)
假設,如果我們需要得到的累計總和為一組,使用cumsum
通過與“TBL”的列循環后apply
。
tbl1 <- apply(tbl, 2, cumsum)
標簽( rownames
)可以通過更改sub
匹配后面的括號(數字(
),與1更換。
rownames(tbl1) <- sub('(?<=\\()\\d+', '1', rownames(tbl1), perl=TRUE)
tbl1
# sumDF
# -3000 -1000 0 1000 2000 3000 4000 5000
#(1,5] 0 0 0 0 0 0 0 0
#(1,10] 0 0 0 0 0 0 0 0
#(1,20] 0 0 0 0 0 0 0 0
#(1,30] 0 0 0 0 0 0 0 0
#(1,40] 0 0 0 0 0 0 0 0
#(1,50] 0 0 0 0 0 0 0 0
#(1,60] 0 0 0 0 0 0 0 0
#(1,70] 0 0 0 0 0 0 0 0
#(1,80] 0 0 0 0 0 0 0 0
#(1,90] 0 0 0 0 0 0 0 0
#(1,95] 0 0 0 0 0 0 0 0
#(1,99] 0 0 0 0 0 0 0 0
注意:根據dput示例,頻率全為0。
我們還可以通過使用labels
參數在cut
本身內更改labels
。 我們創建一個自定義標簽('lvls'),並在cut
使用它。 除此之外,下面的代碼與上面的類似。
lvls <- paste0('(', '1,', c(5,seq(10,90, by=10), 95, 99), ']')
tbl <- table(sumDF, cut(sumDF, breaks=levellength, labels=lvls))
apply(tbl, 1, cumsum)
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