[英]How to convert list pairs into tuple pairs
如何通過使用簡單的編程(例如for循環)將包含對的列表轉換為包含元組對的列表? x,y = ...?
我的代碼:
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
numbers.split(',')
x,y = tuple numbers
return numbers
需求輸出:
[(68,125), (113,69), (65,86), (108,149), (152,53), (78,90)]
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
return [tuple(map(int,pair.split(','))) for pair in numbers]
通過使用嵌套列表理解來嘗試此操作:
o = [tuple(int(y) for y in x.split(',')) for x in numbers]
只需使用列表理解即可。 在這里閱讀更多信息!
# Pass in numbers as an argument so that it will work
# for more than 1 list.
def read_numbers(numbers):
return [tuple(int(y) for y in x.split(",")) for x in numbers]
這是列表理解的細分和解釋(用注釋):
[
tuple( # Convert whatever is between these parentheses into a tuple
int(y) # Make y an integer
for y in # Where y is each element in
x.split(",") # x.split(","). Where x is a string and x.split(",") is a list
# where the string is split into a list delimited by a comma.
) for x in numbers # x is each element in numbers
]
但是,如果僅對一個列表進行操作,則無需創建函數。
嘗試這個 :
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
final_list = []
[final_list.append(tuple(int(test_str) for test_str in number.split(','))) for number in numbers]
return final_list
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