如何将列表对转换为元组对

Question

如何通过使用简单的编程（例如for循环）将包含对的列表转换为包含元组对的列表？ x，y = ...？

我的代码：

def read_numbers():
    numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
    numbers.split(',')
    x,y = tuple numbers
    return numbers

需求输出：

[(68,125), (113,69), (65,86), (108,149), (152,53), (78,90)]

Answer 1

def read_numbers():
    numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
    return [tuple(map(int,pair.split(','))) for pair in numbers]

Answer 2

通过使用嵌套列表理解来尝试此操作：

o = [tuple(int(y) for y in x.split(',')) for x in numbers]

Answer 3

只需使用列表理解即可。 在这里阅读更多信息！

# Pass in numbers as an argument so that it will work
# for more than 1 list.
def read_numbers(numbers):
    return [tuple(int(y) for y in x.split(",")) for x in numbers]

这是列表理解的细分和解释（用注释）：

[
    tuple(                              # Convert whatever is between these parentheses into a tuple
            int(y)                      # Make y an integer
            for y in                    # Where y is each element in
            x.split(",")                # x.split(","). Where x is a string and x.split(",") is a list
                                        # where the string is split into a list delimited by a comma.
    ) for x in numbers                  # x is each element in numbers
]

但是，如果仅对一个列表进行操作，则无需创建函数。

Answer 4

尝试这个 ：

def read_numbers():
    numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
    final_list = []
    [final_list.append(tuple(int(test_str) for test_str in number.split(','))) for number in numbers]
    return final_list