How do you turn a list that contain pairs into a list that contains tuple pairs by using easy programming eg for loop? x,y = ...?
My code:
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
numbers.split(',')
x,y = tuple numbers
return numbers
desire output:
[(68,125), (113,69), (65,86), (108,149), (152,53), (78,90)]
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
return [tuple(map(int,pair.split(','))) for pair in numbers]
通过使用嵌套列表理解来尝试此操作:
o = [tuple(int(y) for y in x.split(',')) for x in numbers]
Just use list comprehension. Read more about it here !
# Pass in numbers as an argument so that it will work
# for more than 1 list.
def read_numbers(numbers):
return [tuple(int(y) for y in x.split(",")) for x in numbers]
Here is a breakdown and explanation (in comments) of the list comprehension:
[
tuple( # Convert whatever is between these parentheses into a tuple
int(y) # Make y an integer
for y in # Where y is each element in
x.split(",") # x.split(","). Where x is a string and x.split(",") is a list
# where the string is split into a list delimited by a comma.
) for x in numbers # x is each element in numbers
]
However, if you are just doing it for one list, there is no need to create a function.
Try this :
def read_numbers():
numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
final_list = []
[final_list.append(tuple(int(test_str) for test_str in number.split(','))) for number in numbers]
return final_list
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