如何在按下按鈕時關閉彈出窗口，並在打開彈出窗口的窗口上發起回發？

Question

往上看...

Answer 1

您應該能夠在window.parent中調用函數。

<script type="text/javascript">
    function closeThisPopupWindow()
    {
        if (window.parent && window.parent.callBack)
            window.parent.callBack();
        window.close();
    }
</script>

顯然，您需要將closeThisPopupWindow函數附加到您的按鈕。

Answer 2

嘗試這樣的事情：

parent.document.getElementById('btnSubmit').click();; // submit the parent form
self.close(); // close the current window

Answer 3

我會在彈出窗口的按鈕單擊中執行類似操作

ClientScript.RegisterStartupScript(typeof(string), "auto_refreshparent", @" window.opener.location.reload(); ", true);
ClientScript.RegisterStartupScript(typeof(Page), "ThatsAllFolks", "window.close();", true);

Answer 4

字符串windowArgs =“ toolbar = no，menubar = no，location = no，width = 620，height = 500，scrollbars = yes，resizable = yes，modal = yes”; 字符串newWindowUrl =“ MarketShotPreview.aspx”; 字符串javaScript =“ \\ n” +“ \\ n” +“ \\ n”; ClientScript.RegisterStartupScript（typeof（System.Web.UI.Page），“ Popup”，javaScript）;