Python-生成相同的隨機數

Question

def main():
    x = [randint(1,100) for i in range(1,100)]
    return x

這將返回100和1和100之間的隨機數。每次調用該函數時，它都會返回不同的數字序列。 我想要的是每次都獲得相同的數字序列。 也許將結果保存到某物？

Answer 1

您可以提供一些固定的種子。

import random

def main():
    random.seed(9001)
    x = [random.randint(1,100) for i in range(1,100)]
    return x

有關種子的更多信息： random.seed（）：它是做什么的？

Answer 2

這是在您的代碼之后構圖的一個基本示例

import random
s = random.getstate()

print([random.randint(1,100) for i in range(10)])

random.setstate(s)
print([random.randint(1,100) for i in range(10)])

在這兩個調用中，您將獲得相同的輸出。 關鍵是，您可以隨時檢索並稍后重新分配rng的當前狀態。

Answer 3

In [19]: for i in range(10):
    ...:     random.seed(10)
    ...:     print [random.randint(1, 100) for j in range(5)]
    ...:
    ...:
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]

必須在重新調用random之前調用random.seed函數。

In [20]: random.seed(10)

In [21]: for i in range(10):
    ...:     print [random.randint(1,10) for j in range(10)]
    ...:
[5, 6, 3, 9, 9, 7, 2, 6, 4, 3]
[10, 10, 1, 9, 7, 4, 3, 7, 5, 7]
[7, 2, 8, 10, 10, 7, 1, 1, 2, 10]
[4, 4, 9, 4, 6, 5, 1, 6, 9, 2]
[3, 5, 1, 5, 9, 7, 6, 9, 2, 6]
[4, 7, 2, 8, 1, 2, 9, 10, 5, 5]
[3, 3, 7, 2, 2, 5, 2, 7, 9, 8]
[5, 4, 5, 1, 8, 4, 4, 1, 5, 6]
[4, 9, 7, 3, 6, 10, 6, 7, 1, 5]
[5, 5, 5, 6, 6, 5, 2, 5, 10, 5]