[英]Adding Multiple Regression Line Equations, R2 and SSE on the same graph
在R中,我使用stat_poly_eq()
注釋繪圖中線性模型的方程,遇到兩個問題:
如何注釋三個單獨的方程式,一個方程式用於每個組,另一個方程式用於整個數據?
如何在每個方程式上加上相應的平方誤差和(SSE)?
如所示在這里 ,下面的代碼產生包括所有數據的一般方程:
x <- runif(200, 0, 100)
y <- 5*x + rnorm(200, 0, 10)
df <- data.frame(x, y)
df$GENDER[1:100] <- 1
df$GENDER[101:nrow(df)] <- 2
formula <- y ~ poly(x, 1, raw = TRUE)
my_features <- list(scale_shape_manual(values=c(16, 1)),
geom_smooth(method = "lm", aes(group = 1),
formula = formula, colour = "Black",
fill = "grey70"),
geom_smooth(method = "lm", aes(group = factor(GENDER), se = F),
formula = formula, colour = "Black"),
stat_poly_eq(aes(label = paste(..eq.label.., ..rr.label.., sep = "~~~~")),
formula = formula, parse = TRUE)
)
ggplot(df, aes(x = x, y = y, aes(shape = factor(GENDER)))) +
geom_point(aes(shape = factor(GENDER))) +
my_features
我必須手動添加誤差平方和,然后根據完整的數據集定位方程式。 使用以下方法。
library(ggplot2)
library(ggpmisc)
# Get Error Sum of Squares
sum((lm(y ~ poly(x, 1, raw = TRUE)))$res^2)
sum(lm(y[df$GENDER == 1] ~ poly(x[df$GENDER == 1], 1, raw = TRUE))$res^2)
sum(lm(y[df$GENDER == 2] ~ poly(x[df$GENDER == 2], 1, raw = TRUE))$res^2)
my_features <- list(
scale_shape_manual(values=c(16, 1)),
geom_smooth(method = "lm", aes(group = 1),
formula = formula, colour = "Black", fill = "grey70"),
#Added colour
geom_smooth(method = "lm", aes(group = factor(GENDER), colour = factor(GENDER)),
formula = formula, se = F),
stat_poly_eq(
aes(label = paste(paste(..eq.label.., ..rr.label.., sep = "~~~~"),
#Manually add in ESS
paste("ESS", c(9333,9622), sep = "=="),
sep = "~~~~")),
formula = formula, parse = TRUE)
)
ggplot(df, aes(x = x, y = y, shape = factor(GENDER), colour = factor(GENDER))) +
geom_point(aes(shape = factor(GENDER))) +
my_features +
#Add in overall line and label
geom_smooth(method = "lm", aes(group = 1), colour = "black") +
stat_poly_eq(aes(group = 1, label = paste(..eq.label.., ..rr.label.., 'ESS==19405', sep = "~~~~")),
formula = formula, parse = TRUE, label.y = 440)
或者,您可以復制您的數據集,因此完整的數據集本身就包含在一個因子級別中...仍然需要手動添加ESS。
x <- runif(200, 0, 100)
y <- 5*x + rnorm(200, 0, 10)
df1 <- data.frame(x, y)
df1$GENDER[1:100] <- 1
df1$GENDER[101:nrow(df1)] <- 2
df2 <- df1
df2$GENDER <- 3
#Now data with GENDER == 3 is the full data
df <- rbind(df1, df2)
my_features <- list(
#Add another plotting character
scale_shape_manual(values=c(16, 1, 2)),
#Added colour
geom_smooth(method = "lm", aes(group = factor(GENDER), colour = factor(GENDER)),
formula = formula, se = F),
stat_poly_eq(
aes(label = paste(paste(..eq.label.., ..rr.label.., sep = "~~~~"),
#Manually add in ESS
paste("ESS", c(9333,9622,19405), sep = "=="),
sep = "~~~~")),
formula = formula, parse = TRUE)
)
ggplot(df, aes(x = x, y = y, shape = factor(GENDER), group = factor(GENDER), colour = factor(GENDER))) +
geom_point(aes(shape = factor(GENDER))) +
my_features
編輯:如果要刪除第三組的打印字符,也可以這樣做。
my_features <- list(
geom_smooth(method = "lm", aes(group = factor(GENDER), colour = factor(GENDER)),
formula = formula, se = F),
stat_poly_eq(
aes(label = paste(paste(..eq.label.., ..rr.label.., sep = "~~~~"),
#Manually add in ESS
paste("ESS", c(9333,9622,19405), sep = "=="),
sep = "~~~~")),
formula = formula, parse = TRUE)
)
p <- ggplot(df, aes(x = x, y = y, shape = factor(GENDER), group = factor(GENDER), colour = factor(GENDER))) +
my_features
p +
scale_color_manual(labels = c("Male", "Female", "Both"), values = hue_pal()(3)) +
geom_point(data = df[df$GENDER == 1,], aes(colour = factor(GENDER)), shape = 16)+
geom_point(data = df[df$GENDER == 2,], aes(colour = factor(GENDER)), shape = 1) +
guides(colour = guide_legend(title = "Gender", override.aes = list(shape = NA)))
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