為什么代碼體沒有給出相同的結果？

Question

下面的代碼顯示了列表中最不經常重復的數字，並且可以正常工作，並給出了答案3 ...

    theList = [1,3,1,2,2]
listCheck, least = len(theList), 0
for theLeast in theList:
    if theList.count(theLeast) <= listCheck :
        listCheck = theList.count(theLeast)
        least = theLeast
print (least)

但是，當我定義列表並將其更改為整數序列時，代碼顯示1是最不常見的？

 def The_uncommon(integers):
    theList = integers
    listCheck, least = len(theList), 0
    for theLeast in theList:
        if theList.count(theLeast) <= listCheck :
            listCheck = theList.count(theLeast)
            least = theLeast
            return (least)
print(The_uncommon([1,3,1,2,2]))

歡迎任何建議

Answer 1

注意縮進 。 :)

在第一個代碼段中，您要遍歷整個循環，而在第二個定義函數的示例中，您將返回第一個 least事件。

Answer 2

python的經典縮進問題。

   def The_uncommon(integers):
        theList = integers
        listCheck, least = len(theList), 0
        for theLeast in theList:
            if theList.count(theLeast) <= listCheck :
                listCheck = theList.count(theLeast)
                least = theLeast
        return (least)
    print(The_uncommon([1,3,1,2,2]))