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[英]how to add number of days to the date given in a jtextfield with string data type
[英]ABAP: How to add days to a date of type TIMESTAMP
在ABAP編程語言中,如何在TIMESTAMP
類型的時間內添加1天並正確地滾動月份/年?
例如:
data lv_time type TIMESTAMP value '20180228000000'.
data(lv_new_time) = lv_time + 1. " should be '20180301000000', but instead is '20180228000001'
data(lv_new_time2) = lv_time + 1000000. " should be '20180301000000', but instead is '20180229000000'
在查看Jagger的回答之后,我查看了TIMESTAMP_DURATION_ADD
函數的TIMESTAMP_DURATION_ADD
並發現了一些ABAP語法,它完成了這項工作而根本不需要函數調用。
constants: lc_time_zone type timezone value 'UTC'.
data lv_timestamp_before type timestamp value '20180228001234'.
data lv_timestamp_after type timestamp.
data lv_date like sy-datum.
data lv_time like sy-uzeit.
convert time stamp lv_timestamp_before time zone lc_time_zone
into date lv_date time lv_time.
lv_date = lv_date + 1.
convert date lv_date time lv_time
into time stamp lv_timestamp_after time zone lc_time_zone.
這是一個適合您的解決方案。 系統中應該可用的功能模塊是TIMESTAMP_DURATION_ADD
。
REPORT zzz.
DATA lv_time TYPE timestamp VALUE '20180228000000'.
START-OF-SELECTION.
DATA timestamp_out TYPE timestamp.
CALL FUNCTION 'TIMESTAMP_DURATION_ADD'
EXPORTING
timestamp_in = lv_time
timezone = 'UTC'
duration = 1
unit = 'TAG' " day (in German)
IMPORTING
timestamp_out = timestamp_out
EXCEPTIONS
timestamp_error = 1
OTHERS = 2.
ASSERT sy-subrc = 0.
WRITE timestamp_out.
如果您不想恢復舊的過程編程,則可以使用文檔中描述的CL_ABAP_TSTMP
類。
DATA some_timestamp TYPE timestamp VALUE '20180228000000'.
DATA(new_timestamp) = cl_abap_tstmp=>add(
tstmp = some_timestamp
secs = ( 365 * 24 * 60 * 60 )
).
(太糟糕了CL_ABAP_TSTMP=>SECSOFDAY
是私人的...但是嘿,至少那會讓你想到如何處理閏年......)
您可以使用FM IAM_TIMESTAMP_CALC將一天添加到時間戳,結果將為20180301000000:
DATA lv_time TYPE timestamp VALUE '20180228000000'.
CALL FUNCTION 'IAM_TIMESTAMP_CALC'
EXPORTING
iv_refdate = lv_time
* IV_XBACKWARD =
iv_days = '1'
* IV_HOURS = '0'
* IV_MINUTES = '0'
* IV_SECONDS = '0'
IMPORTING
ev_date = lv_time.
我不確定它是否會起作用,但也許值得一試。
提取時間戳的日期,將日期添加一天,然后使用新日期和時間戳的其余部分創建新的時間戳。
就像是
data: stamp type timestamp value '20180301000000000',
stamp_date type dats,
new_stamp type timestamp.
stamp_date = stamp(8). "if it doesn't work, just look for a FM
add 1 to stamp_date.
new_stamp = stamp_date && stamp+8.
我不確定它是否會“按原樣”起作用,但我很確定你能找到一種方法讓它在那里工作......而我們都在等待正確的答案;)
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