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Python:高效地從2D的不規則網格插入到常規網格

[英]Python: Efficiently interpolate from an irregular grid to a regular grid in 2D

我在不規則間隔的2d網格中有一些數據點,我想將這些數據點插入到常規網格中。 例如,假設源數據來自魚眼鏡頭:
不規則源網格的示例。 注意...這些僅是示例-通常,源數據也可能以不同的方式失真-但仍來自網格。

# Source Data
x_src  # A (n_src_rows, n_src_cols) array of x-coordinates of points
y_src  # A (n_src_rows, n_src_cols) array of y-coordinates of points
       # (x_src, y_src) form an irregular grid.  i.e. if you were to plot the lines connecting neighbouring points, no lines would ever cross.
f_src  # A (n_src_rows, n_src_cols) array of values.

# Interpolation Points: 
x_dst  # An (n_dest_cols) sorted array of x-coordinates of columns in a regular grid
y_dst  # An (n_dest_rows) sorted array of y-coordinates of rows in a regular grid.

# Want to calculate:
f_dst  # An (n_dest_rows, n_dest_cols) array of interpolated data on the regular grid defined by x_dst, y_dst

到目前為止,我一直在使用scipy.interpolate.griddata ,並將源點展平到一維數組中,但這有點慢,因為它沒有利用源數據點的網格結構(僅目標數據點) )。 它還在不在相鄰源網格點內部的區域內插(如果源網格的邊界是凹形的,則會發生這種情況(如左圖所示)。

在SciPy / opencv或某些類似的庫中,當源數據位於不規則間隔的網格中時,是否可以有效地進行插值?

好吧,它仍然不是最佳的,因為它沒有利用已知的源數據沿網格放置的事實,但是到目前為止,我發現的最佳方法是使用SciPy的NearestNDInterpolator,該方法基於KDTree:

import scipy.interpolate 

def fast_interp_irregular_grid_to_regular(
        x_dst,  # type: ndarray(dst_size_x)  # x-values of columns in the destination image.
        y_dst,  # type: ndarray(dst_size_y)  # y-values of rows in the destination image
        x_src,  # type: ndarray(src_size_y, src_sixe_x)   # x-values of data points
        y_src,  # type: ndarray(src_size_y, src_size_x)   # y-values of data points
        f_src,  # type: ndarray(src_size_y, src_size_x, n_dim)  # values of data points.
        fill_value = 0,  # Value to fill in regions outside pixel hull
        zero_edges = True,  # Zero the edges (ensures that regions outside source grid are zero)
    ):  # type: (...) -> array(dst_size_y, dst_size_x, n_dim)  # Interpolated image
    """
    Do a fast interpolation from an irregular grid to a regular grid.  (When source data is on a grid we can interpolate
    faster than when it consists of arbitrary points).

    NOTE: Currently we do not exploit the fact that the source data is on a grid.  If we were to do that, this function
    could be much faster.
    """
    assert zero_edges in (False, True, 'inplace')

    univariate = f_src.ndim==1
    if univariate:
        f_src = f_src[:, None]
    else:
        assert f_src.ndim==3

    if zero_edges:
        if zero_edges is True:
            f_src = f_src.copy()
        f_src[[0, -1], :] = fill_value
        f_src[:, [0, -1]] = fill_value
    interp = scipy.interpolate.NearestNDInterpolator(
        x = np.hstack([x_src.reshape(-1, 1), y_src.reshape(-1, 1)]),
        y = f_src.reshape(-1, f_src.shape[-1]),
    )
    grid_x, grid_y = np.meshgrid(x_dst, y_dst)
    z = interp((grid_x, grid_y)).reshape((len(y_dst), len(x_dst), f_src.shape[-1]))
    return z

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