我的均方根平均值有什么問題？

Question

我一直在研究計算房間均方值的代碼。 我的循環結構似乎出了點問題，有人可以幫助找到我的錯誤嗎？ 謝謝！

def rms():
    print("This program will calculate the RMS of your values.")
    print()
    n = int(input("Please enter the number of values you want 
    calculated: "))
    total = 0.0
for i in range(n):
    x = float(input("Enter a desired values:"))
    total = total + math.sqrt(x)



print("\nThe Root Mean Square is:", math.sqrt(total/n))

Answer 1

沒關系，我從閱讀中看到您想要rms()所有內容，我相信您希望rms()所有內容都應謹慎處理縮進，以使函數的某些部分不會落在函數的范圍之外，但這可以正常工作，但是不確定所需的輸出。

import math

def rms():
    print("This program will calculate the RMS of your values.")
    print()
    n = int(input("Please enter the number of values you want calculated: "))
    total = 0.0 
    for i in range(n):
        x = float(input("Enter a desired values:"))
        total = total + math.sqrt(x)
    print("\nThe Root Mean Square is:", math.sqrt(total/n))

rms()

 (xenial)vash@localhost:~/python/stack_overflow$ python3.7 rms.py This program will calculate the RMS of your values. Please enter the number of values you want calculated: 3 Enter a desired values:10 Enter a desired values:3 Enter a desired values:2 The Root Mean Square is: 1.4501197686295146 

Answer 2

您犯了一個錯誤，其中存在total = total + math.sqrt(x)錯誤是您應該找到x的平方x而不是x的平方根，所以請嘗試我的固定代碼：-

def rms():
    print("This program will calculate the RMS of your values.\n")
    n = int(input("Please enter the number of values you want calculated: "))
    total = 0.0
    for i in range(n):
        x = float(input("Enter a desired values:"))
        total += x ** 2 #it means x powered by two

    print("\nThe Root Mean Square is:", math.sqrt(total/n))

Answer 3

如果我正確地推斷出，那么您想將每個輸入取平方，求和並求平均值，然后求和。 請記住，求平均時（尋找均值），僅需除以最后的和：

def rms():
    total = 0.0
    count = 0
    while True:
        x = input('enter value (enter nothing to stop):')
        if x.strip() == '':
            break
        count += 1
        total += float(x) ** 2

    print('mean square root is:', math.sqrt(total/count))
    # return math.sqrt(total / count)