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[英]Reading multiple Json files and combining into one file as per the date in Python
[英]Python problem: reading multiple json files from a folder load only one json
我的json文件示例帶有以下統計標記:
mean:0,23454
min:-2,83456
max:-3,45678
…
我有一個包含20個json文件的文件夾:
這是我的代碼,用於從Python的文件夾中讀取多個json文件,這是問題Python:從文件夾中讀取多個json文件
此代碼僅加載單個json文件,而不加載多個文件,我也不知道為什么。 我認為問題在於此功能:
for index, js in enumerate(json_files):
with open(os.path.join(path_to_json, js)) as json_file:
json_text = json.load(json_file)
我所有的代碼:
import os, json
import pandas as pd
# this finds our json files
path_to_json = 'path/'
json_files = [pos_json for pos_json in os.listdir(path_to_json) if pos_json.endswith('.json')]
# here I define my pandas Dataframe with the columns I want to get from the json
jsons_data = pd.DataFrame(columns=['mean','min','max','peak2peak','std','variance','kurtosis','skewness','rmsOriginalSignal','rmsFiltSignal_01','rmsFiltSignal_02','rmsFiltSignal_03'])
# we need both the json and an index number so use enumerate()
for index, js in enumerate(json_files):
with open(os.path.join(path_to_json, js)) as json_file:
json_text = json.load(json_file)
mean = json_text['mean']
min = json_text['min']
max = json_text['max']
peak2peak = json_text['peak2peak']
std = json_text['std']
variance = json_text['std']
kurtosis = json_text['kurtosis']
skewness = json_text['skewness']
rmsOriginalSignal = json_text['rmsOriginalSignal']
rmsFiltSignal_01 = json_text['rmsFiltSignal_01']
rmsFiltSignal_02 = json_text['rmsFiltSignal_02']
rmsFiltSignal_03 = json_text['rmsFiltSignal_03']
jsons_data.loc[index]= [mean,min,max,peak2peak,std,variance,kurtosis,skewness,rmsOriginalSignal, rmsFiltSignal_01, rmsFiltSignal_02, rmsFiltSignal_03]
print(jsons_data)
這段代碼沒有給出任何錯誤,但是僅加載一個json文件。
在我看來, json_text
每次迭代json_text
被覆蓋。
也許創建一個列表,然后在循環中追加到該列表?
例如:
json_text_list = []
for index, js in enumerate(json_files):
with open(os.path.join(path_to_json, js)) as json_file:
json_text_list.append(json.load(json_file))
要么在循環中計算您的統計信息(然后將結果存儲在列表或類似列表中)。
您將覆蓋json_text
變量,以便讀取每個文件,但僅保留最后一個文件中的值。 這似乎是因為您的代碼沒有正確縮進。
您將希望縮進最后幾行以匹配循環的縮進,如下所示:
for index, js in enumerate(json_files):
with open(os.path.join(path_to_json, js)) as json_file:
json_text = json.load(json_file)
mean = json_text['mean']
min = json_text['min']
max = json_text['max']
peak2peak = json_text['peak2peak']
std = json_text['std']
variance = json_text['std']
kurtosis = json_text['kurtosis']
skewness = json_text['skewness']
rmsOriginalSignal = json_text['rmsOriginalSignal']
rmsFiltSignal_01 = json_text['rmsFiltSignal_01']
rmsFiltSignal_02 = json_text['rmsFiltSignal_02']
rmsFiltSignal_03 = json_text['rmsFiltSignal_03']
jsons_data.loc[index]= [mean,min,max,peak2peak,std,variance,kurtosis,skewness,rmsOriginalSignal, rmsFiltSignal_01, rmsFiltSignal_02, rmsFiltSignal_03]
print(jsons_data)
為了使示例更容易可視化:
for n in range(10):
n_squared = n * n
print(n_squared)
由於打印語句不在循環中,因此只會打印81
。 像修復建議縮進這種print
將打印每平方值。
for n in range(10):
n_squared = n * n
print(n_squared)
輸出:
0
1
4
9
16
25
36
49
64
81
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