![](/img/trans.png)
[英]Compare columns in two different data frames if match found copy email from df2 to df1
[英]If values from two columns in two different data frames match then copy values from another column in df2 to column in df1
我有兩個數據幀,我想將df2中的“ Result2”列中的值復制到df1中的“ Result1”列中,並將與df2中的值相同的行中的“描述”列從df2添加至df1中如果兩個數據框中的“ ID”列中的值都匹配,則將列“ Result2”(已復制)。
以下是數據幀:
df1
ID Result1
Position1 NaN
MRS1 OK
MRS2 Maybe
MRS3 NOK
Position2 NaN
MRS4 OK
MRS5 OK
Position3 NaN
MRS6 OK
Position4 NaN
MRS7 NOK
MRS8 OK
MRS9 NOK
MRS10 Excellent
df2
ID Result2 Description
text NaN NaN
NaN NaN text
text NaN NaN
MRS1 OK New
MRS2 OK Old
NaN NaN NaN
NaN NaN text
MRS3 OK New
MRS4 OK New
MRS5 OK NaN
MRS6 NOK Very old
NaN text NaN
text text NaN
NaN NaN NaN
MRS7 Excellent Very old
MRS8 Excellent Old
text text text
MRS9 Excellent New
NaN NaN NaN
MRS10 NOK New
我想得到:
ID Result1 Result2
Position1 NaN NaN
MRS1 OK New
MRS2 OK Old
MRS3 OK New
Position2 NaN NaN
MRS4 OK New
MRS5 OK NaN
Position3 NaN NaN
MRS6 NOK Very old
Position4 NaN NaN
MRS7 Excellent Very old
MRS8 Excellent Old
MRS9 Excellent New
MRS10 NOK New
我將NaN放在應該是一個空單元格的地方。 如何在熊貓中做到這一點? 我嘗試了合並,但是我遇到了問題,因為它要求比較列的長度相同。 我只想比較兩個數據幀的“ ID”列中的值,並且這些列的長度不同。
使用僅merge
具有左聯接的列ID
rename
列的merge
:
df = (df1[['ID']].merge(df2, on='ID', how='left')
.rename(columns={'Result2':'Result1','Description':'Result2'}))
print (df)
ID Result1 Result2
0 Position1 NaN NaN
1 MRS1 OK New
2 MRS2 OK Old
3 MRS3 OK New
4 Position2 NaN NaN
5 MRS4 OK New
6 MRS5 OK NaN
7 Position3 NaN NaN
8 MRS6 NOK Very old
9 Position4 NaN NaN
10 MRS7 Excellent Very old
11 MRS8 Excellent Old
12 MRS9 Excellent New
13 MRS10 NOK New
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.