[英]Plot bar graph using matplotlib with different dataframe shape
我有以下三個不同的數據框。前兩個的形狀為(4,),最后一個的形狀為(2,)。 如何轉換數據框的形狀?
當我嘗試在條形圖中繪制所有三個時,最后一個DF失敗,並顯示“ ValueError:形狀不匹配:對象無法廣播為單個形狀”
如何通過將“ Empty”和“ Invalid”顯示為0在同一條形圖中繪制DF3。
DF1:
Validity
Empty 2672
InValid 581
Multiple Entries 282
Valid 5526
Name: Lifecycle, dtype: int64
DF2:
Validity
Empty 1920
InValid 471
Multiple Entries 2325
Valid 33446
Name: Lifecycle, dtype: int64
DF3:
Validity
Multiple Entries 10334
Valid 11984
Name: Lifecycle, dtype: int64
下面是我的代碼。
glot = sample_lot_number.groupby("Validity")
vlot = sample1_lot_number.groupby("Validity")
dplot = Data_Package_Lot_Number.dplot.groupby("Validity")
ind = np.arange(4)
width = 0.15
ax = plt.subplot()
p1 = ax.bar(ind+width,glot.Lifecycle.count(), width)
p2 = ax.bar(ind,vlot.Lifecycle.count(), width)
p3 = ax.bar(ind-width,dplot.Lifecycle.count(), width)
ax.set_xticks(ind + width / 2)
ax.set_xticklabels(("Empty","InValid","Multiple Entries","Valid"))
@busybear在評論中給出了正確的答案。 您的代碼不可運行。 如果我會猜測,可以嘗試以下代碼:
glot = sample_lot_number.groupby("Validity")
vlot = sample1_lot_number.groupby("Validity")
dplot = Data_Package_Lot_Number.dplot.groupby("Validity")
df1 = glot.Lifecycle.count()
df2 = vlot.Lifecycle.count().reindex(df1)
df3 = dplot.Lifecycle.count().reindex(df1).fillna(0)
ind = np.arange(4)
width = 0.15
ax = plt.subplot()
p1 = ax.bar(ind+width, df1, width)
p2 = ax.bar(ind, df2, width)
p3 = ax.bar(ind-width, df3, width)
ax.set_xticks(ind + width / 2)
ax.set_xticklabels(("Empty","InValid","Multiple Entries","Valid"))
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