[英]How to remove specific day timestamps from a big dataframe
我有一個包含600天數據的大數據框。 每天有100個時間戳。 我有一個30天的單獨列表,我想從中獲取數據。 如何從數據框中刪除這30天內的數據? 我嘗試了一個for循環,但它沒有用。 我知道有一個簡單的方法。 但我不知道如何實現它。
df #is main dataframe which has many columns and rows. Index is a timestamp.
df['dates'] = df.index.strftime('%Y-%m-%d') # date part of timestamp is sliced and
#a new column is created. Instead of index, I want to use this column for comparing with bad list.
bad_list # it is a list of bad dates
for i in range(0,len(df)):
for j in range(0,len(bad_list)):
if str(df['dates'][i])== bad_list[j]:
df.drop(df[i].index,inplace=True)
您可以執行以下操作
df['dates'] = df.index.strftime('%Y-%m-%d')
#badlist should be in date format too.
newdf = df[~df['dates'].isin(badlist)]
# the ~ is used to denote "not in" the list.
#if Jan 1, 2000 is a bad date, it should be in the list as datetime(2000,1,1)
你可以進行簡單的比較:
>>> dates = pd.Series(pd.to_datetime(np.random.randint(int(time()) - 60 * 60 * 24 * 5, int(time()), 12), unit='s'))
>>> dates
0 2019-03-19 05:25:32
1 2019-03-20 00:58:29
2 2019-03-19 01:03:36
3 2019-03-22 11:45:24
4 2019-03-19 08:14:29
5 2019-03-21 10:17:13
6 2019-03-18 09:09:15
7 2019-03-20 00:14:16
8 2019-03-21 19:47:02
9 2019-03-23 06:19:35
10 2019-03-23 05:42:34
11 2019-03-21 11:37:46
>>> start_date = pd.to_datetime('2019-03-20')
>>> end_date = pd.to_datetime('2019-03-22')
>>> dates[(dates > start_date) & (dates < end_date)]
1 2019-03-20 00:58:29
5 2019-03-21 10:17:13
7 2019-03-20 00:14:16
8 2019-03-21 19:47:02
11 2019-03-21 11:37:46
如果源Series
不是datetime
格式,則需要使用pd.to_datetime
進行轉換。
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