[英]How do I convert a time string like "last Sunday" or "Next Monday" into datetime format in python
我正在嘗試找到一種使用 python 3 將“上周日”或“下周一”之類的時間字符串轉換為 DateTime 格式的方法。我嘗試使用以下方法:
x = datetime.strptime("Sunday", "%A")
但它給出了這樣的輸出:
1900-01-01 00:00:00
我想知道如何獲取與當前日期相關的日期!
謝謝 :)
我的建議:建立一個輔助索引以找出一天之前或之前的天數,然后使用timedelta
。 下面的代碼應該展示我的意思,不是超級 Pythonic,但它可以為您的示例提供技巧。
from datetime import datetime
from datetime import timedelta
now = datetime.now()
nowDayString = now.strftime("%A")
days = [
"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday",
"Saturday",
"Sunday"
]
def buildLut():
floatingDays = [""]*8
for idx, day in enumerate(days):
if day == nowDayString:
floatingDays[0] = nowDayString
floatingDays[7] = nowDayString
for i, j in zip(range(idx+1, len(days)), range(1, len(days))):
floatingDays[j] = days[i]
for i in range(idx):
floatingDays[7-(idx-i)] = days[i]
return floatingDays
def findme(s):
td = timedelta()
dayToLookFor = s.split(" ")[1]
if "last" in s.lower():
td = timedelta(days=-(7 - floatingDays.index(dayToLookFor)))
elif "next" in s.lower():
td = timedelta(days=floatingDays.index(dayToLookFor))
return now + td
floatingDays = buildLut()
print(floatingDays)
print(findme("last Sunday"))
print(findme("Next Monday"))
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