Python Pandas - 生成列的總和，該列的值為“1”或 NaN

Question

我有一個看起來像這樣的數據框

Opened              Closed              Resolved                   07:01 - 09:00    09:01 - 11:00   11:01 - 13:00   
2020-04-14 14:45:58 2020-04-14 15:04:22 0 days 00:18:24.000000000                                   1   
2020-04-14 13:43:28 2020-04-14 14:12:22 0 days 00:28:54.000000000                   1   
2020-04-14 13:41:18 2020-04-14 14:12:28 0 days 00:31:10.000000000                   1   
2020-04-14 10:57:53 2020-04-14 11:24:58 0 days 00:27:05.000000000       1           
2020-04-14 09:18:14 2020-04-14 09:44:04 0 days 00:25:50.000000000       1           
2020-04-14 09:16:28 2020-04-14 09:31:12 0 days 00:14:44.000000000       1           
2020-04-13 22:56:09 2020-04-14 00:39:30 0 days 01:43:21.000000000                   
2020-04-13 20:10:31 2020-04-13 20:26:25 0 days 00:15:54.000000000                   
2020-04-13 08:29:38 2020-04-13 18:29:25 0 days 09:59:47.000000000       1               
2020-04-09 14:04:14 2020-04-09 15:31:01 0 days 01:26:47.000000000                   1   
2020-04-09 10:06:24 2020-04-09 10:33:39 0 days 00:27:15.000000000       1           
2020-04-08 21:38:13 2020-04-09 07:01:30 0 days 09:23:17.000000000                   
2020-04-08 15:51:41 2020-04-08 16:08:02 0 days 00:16:21.000000000                                   1
2020-04-08 15:50:09 2020-04-08 16:07:57 0 days 00:17:48.000000000                                   1
2020-04-08 15:48:38 2020-04-08 16:07:52 0 days 00:19:14.000000000                                   1

我想在每列的底部生成所有“1”值的總和，所以它看起來像這樣。

Opened              Closed              Resolved                   07:01 - 09:00    09:01 - 11:00   11:01 - 13:00   
2020-04-14 14:45:58 2020-04-14 15:04:22 0 days 00:18:24.000000000                                   1   
2020-04-14 13:43:28 2020-04-14 14:12:22 0 days 00:28:54.000000000                   1   
2020-04-14 13:41:18 2020-04-14 14:12:28 0 days 00:31:10.000000000                   1   
2020-04-14 10:57:53 2020-04-14 11:24:58 0 days 00:27:05.000000000       1           
2020-04-14 09:18:14 2020-04-14 09:44:04 0 days 00:25:50.000000000       1           
2020-04-14 09:16:28 2020-04-14 09:31:12 0 days 00:14:44.000000000       1           
2020-04-13 22:56:09 2020-04-14 00:39:30 0 days 01:43:21.000000000                   
2020-04-13 20:10:31 2020-04-13 20:26:25 0 days 00:15:54.000000000                   
2020-04-13 08:29:38 2020-04-13 18:29:25 0 days 09:59:47.000000000       1               
2020-04-09 14:04:14 2020-04-09 15:31:01 0 days 01:26:47.000000000                   1   
2020-04-09 10:06:24 2020-04-09 10:33:39 0 days 00:27:15.000000000       1           
2020-04-08 21:38:13 2020-04-09 07:01:30 0 days 09:23:17.000000000                   
2020-04-08 15:51:41 2020-04-08 16:08:02 0 days 00:16:21.000000000                                   1
2020-04-08 15:50:09 2020-04-08 16:07:57 0 days 00:17:48.000000000                                   1
2020-04-08 15:48:38 2020-04-08 16:07:52 0 days 00:19:14.000000000                                   1

Total                                                                   5           3               4                 
12

所以每一列都有自己的總結，然后所有列也有一個總數。

我試過了

data.groupby('Total')["07:01 - 09:00"].sum()[1]

但這會輸出一長串'1' 11111111111

我如何實際獲得總數？

Answer 1

鑒於您提供的示例，可能您的三 (3) 列名為 ("07:01 - 09:00, 09:01 - 11:00, 11:01 - 13:00") 是 dtype: str，這就是您的原因得到一長串的 1。 就是說，您應該將列轉換為浮動，如下所示：

data['07:01 - 09:00'] = data['07:01 - 09:00'].astype(float)
data['09:01 - 11:00'] = data['09:01 - 11:00'].astype(float)
data['11:01 - 13:00'] = data['11:01 - 13:00'].astype(float)

之后，您可以嘗試以下操作：

data = data.append(data[['07:01 - 09:00', '09:01 - 11:00', '11:01 - 13:00']].sum(), 
                   ignore_index=True)