從 excel 行讀取逗號分隔的數字 - python pandas

Question

如何讀取 excel 行並檢查第一行的數字是否與第二行和第三行（第四、第五、第六和第七行）的數字相同？ 我想在創建結果之前添加用戶定義的迭代次數。

我只有一列和 7 行，有 6 個逗號分隔的數字。

這是基於 2 次迭代的示例：

column 1
1.) 1,2,3,4,5,6
2.) 1,3,5,7,9,10    ---> 1,3,5
3.) 3,5,7,9,10,11   ---> 3,5

---

分組數字結果（除第一行之外的每一行）：3,5

想法？ E.

Answer 1

鑒於您有此文件：

df = pd.read_excel(io='path_to_file.xlsx', header=None)

print(df)
# Output:
             0
0    1, 2, 3, 4, 5, 6
1   1, 3, 5, 7, 9, 10
2  3, 5, 7, 9, 10, 11

你可以試試這個：

# Setup
previous_row = df.iloc[0]
user_number_of_iterations = 4  # for instance
items = []

# Iterate over dataframe rows and find common values
# between  row[n] and row[n-1]
for i, row in df.iterrows():
    if i == 0:
        continue
    if i > user_number_of_iterations:
        break
    a = set(sorted(row.values[0].split(", ")))
    b = set(sorted(previous_row.values[0].split(", ")))
    items.append(a & b)
    previous_row = row
    # Get symmetric difference between two sets
    print(f"Missed numbers at iteration {i}: {a ^ b}")

# Find common values between previous results
result = items[0]
for item in items[1:]:
    result = set(result) & set(item)

print(sorted(result))  # Output: ['3', '5']

# Missed numbers at iteration 1: {'7', '4', '2', '10', '6', '9'}
# Missed numbers at iteration 2: {'11', '1'}

Answer 2

你可以試試這個 -

假設您有一個逗號分隔的 csv 文件。

from functools import reduce
result = reduce(lambda x,y: x.intersection(y), df.apply(set, axis=1).values) # {3,5}