當特定項目出現時，如何將數組溢出到多個 arrays 中？

Question

那么有沒有辦法在特定項目出現時將數組溢出到多個？ 例如，我想在每次SPILT到來時切斷並溢出陣列。 結果應該是這樣的：

original = ["item", "anotherItem", "SPILT", "Item1", "item2"]
array1 = ["item", "anotherItem"]
array2 = ["Item1", "item2"]

數組也可以改變，所以SPILT的索引是不確定的。

Answer 1

如果SPILT只出現一次，這應該有效：

array1 = original[:original.index('SPILT')]
array2 = original[original.index('SPILT')+1:]

Answer 2

original = ["item", "anotherItem", "SPILT", "Item1", "item2"]

#Is the final array which contains all the split arrays
newarr = []
#Is a temporary array that stores the current chain of elements
currarr = []
for i in original:
    #if the splitting keyword is reached
    if i=="SPILT":
        #put all the current progress as a new array element, start afresh
        newarr.append(currarr)
        currarr = []
    else:
        #just add the element to the current progress
        currarr.append(i)
#add the final split segment of the array into the array of split segments
newarr.append(currarr)

print(newarr)

評論有必要的解釋。 直觀的解決方案。

Answer 3

divider = original.index("SPILT")
print(divider)

array1 = original[:divider]
array2 = original[divider+1:]
print(f"{array1}, \n{array2}")

Answer 4

如果 SPLIT 發生多次，那么這應該有效。

original = ["item", "anotherItem", "SPLIT", "Item1", "item2", "SPLIT", "Item3", "item4"]
if 'SPLIT' in original:    
    test = '$'.join(original)
    splited_arrays = [data.split('$') for data in test.split('$SPLIT$')]