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[英]Is this the Pandas equivalent of SQL Dense Rank over a Sorted Partition?
[英]Pandas equivalent to dense rank
我正在嘗試在 pandas 中復制密集等級 SQL 語句。 SQL 語句如下所示:
,DENSE_RANK() OVER(PARTITION BY [Team],[Season] ORDER BY [Team],
[Season],CAST([characteristic].[value] AS INT) DESC) AS ROW#
到目前為止,我嘗試過的 python 代碼只排在一列上,而不是兩列。
df['Rank'] = df1.Team.rank(method='dense').astype(int)
有沒有人有更好的解決方案?
IIUC 用途:
df[['Rank1', 'Rank2']] = df1[['Team','Season']].rank(method='dense').astype(int)
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