PYTHON中索引的兩個倍數arrays之間的差異

Question

大家好，我剛開始編程，我正在努力做到這一點。

A = [['1','Jack','33'], ['2','Maria','23'], ['3','Christian','9'] ] 
B = [['1','Jack','33'], ['2','Maria','23'], ['3','Christian','9'], ['4','Denis','45'] ]

我想檢查數組B[0]並打印出“4 Denis 45”

Answer 1

我不確定你想要什么。 是這個嗎：

A_ids = [item[0] for item in A]
for lst in B:
    if lst[0] not in A_ids:
        # You can do whatever you want to do with lst at this point
        print(" ".join(lst))

Output：

4 Denis 45