[英]Python summing up time
在python中我如何總結以下時間?
0:00:00
0:00:15
9:30:56
這取決於您擁有這些時間的形式,例如,如果您已經將它們作為datetime.timedelta
s,那么您可以將它們總結起來:
>>> s = datetime.timedelta(seconds=0) + datetime.timedelta(seconds=15) + datetime.timedelta(hours=9, minutes=30, seconds=56)
>>> str(s)
'9:31:11'
使用 timedeltas(在 Python 3.9 中測試):
import datetime
timeList = ['0:00:00', '0:00:15', '9:30:56']
mysum = datetime.timedelta()
for i in timeList:
(h, m, s) = i.split(':')
d = datetime.timedelta(hours=int(h), minutes=int(m), seconds=int(s))
mysum += d
print(str(mysum))
結果:
9:31:11
作為字符串列表?
timeList = [ '0:00:00', '0:00:15', '9:30:56' ]
totalSecs = 0
for tm in timeList:
timeParts = [int(s) for s in tm.split(':')]
totalSecs += (timeParts[0] * 60 + timeParts[1]) * 60 + timeParts[2]
totalSecs, sec = divmod(totalSecs, 60)
hr, min = divmod(totalSecs, 60)
print "%d:%02d:%02d" % (hr, min, sec)
結果:
9:31:11
如果沒有更多的pythonic解決方案,我真的很失望...... :(
可怕的一個->
timeList = [ '0:00:00', '0:00:15', '9:30:56' ]
ttt = [map(int,i.split()[-1].split(':')) for i in timeList]
seconds=reduce(lambda x,y:x+y[0]*3600+y[1]*60+y[2],ttt,0)
#seconds == 34271
這個看起來也太可怕了->
zero_time = datetime.datetime.strptime('0:0:0', '%H:%M:%S')
ttt=[datetime.datetime.strptime(i, '%H:%M:%S')-zero_time for i in timeList]
delta=sum(ttt,zero_time)-zero_time
# delta==datetime.timedelta(0, 34271)
# str(delta)=='9:31:11' # this seems good, but
# if we have more than 1 day we get for example str(delta)=='1 day, 1:05:22'
真郁悶的也是這個->
sum(ttt,zero_time).strftime('%H:%M:%S') # it is only "modulo" 24 :(
我真的很喜歡看單線,所以我嘗試在 python3 中制作一個:P(效果不錯但看起來很糟糕)
import functools
timeList = ['0:00:00','0:00:15','9:30:56','21:00:00'] # notice additional 21 hours!
sum_fnc=lambda ttt:(lambda a:'%02d:%02d:%02d' % (divmod(divmod(a,60)[0],60)+(divmod(a,60)[1],)))((lambda a:functools.reduce(lambda x,y:x+y[0]*3600+y[1]*60+y[2],a,0))((lambda a:[list(map(int,i.split()[-1].split(':'))) for i in a])(ttt)))
# sum_fnc(timeList) -> '30:40:11'
假設您想將總時間的秒數相加:
def parse_time(s):
hour, min, sec = s.split(':')
try:
hour = int(hour)
min = int(min)
sec = int(sec)
except ValueError:
# handle errors here, but this isn't a bad default to ignore errors
return 0
return hour * 60 * 60 + min * 60 + sec
print parse_time('0:00:00') + parse_time('0:00:15') + parse_time('9:30:56')
lines = ["0:00:00", "0:00:15", "9:30:56"]
total = 0
for line in lines:
h, m, s = map(int, line.split(":"))
total += 3600*h + 60*m + s
print "%02d:%02d:%02d" % (total / 3600, total / 60 % 60, total % 60)
from datetime import timedelta
h = ['3:00:00','1:07:00', '4:00:00', '4:05:00', '4:10:00', '4:03:00']
def to_td(h):
ho, mi, se = h.split(':')
return timedelta(hours=int(ho), minutes=int(mi), seconds=int(se))
print(str(sum(map(to_td, h), timedelta())))
# Out[31]: 20:25:00
天真的方法(無異常處理):
#!/usr/bin/env python
def sumup(*times):
cumulative = 0
for t in times:
hours, minutes, seconds = t.split(":")
cumulative += 3600 * int(hours) + 60 * int(minutes) + int(seconds)
return cumulative
def hms(seconds):
"""Turn seconds into hh:mm:ss"""
hours = seconds / 3600
seconds -= 3600*hours
minutes = seconds / 60
seconds -= 60*minutes
return "%02d:%02d:%02d" % (hours, minutes, seconds)
if __name__ == '__main__':
print hms(sumup(*("0:00:00", "0:00:15", "9:30:56")))
# will print: 09:31:11
Bellow 是使用列表理解的解決方案:
from datetime import timedelta
def time_sum(time: List[str]) -> timedelta:
"""
Calculates time from list of time hh:mm:ss format
"""
return sum(
[
timedelta(hours=int(ms[0]), minutes=int(ms[1]), seconds=int(ms[2]))
for t in time
for ms in [t.split(":")]
],
timedelta(),
)
例子:
time_list = ["0:00:00", "0:00:15", "9:30:56"]
total = time_sum(time_list)
print(f"Total time: {total}")
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