statsmodels ARMA预测样本外

Question

I want to predict the return of a time series, I first fitted the data set but it doesn't work when I come to predict the tomorrow's return. My code is

    date = datetime.datetime(2014,12,31)
    todayDate = (date).strftime('%Y-%m-%d')
    startdate = (date - timedelta(days = 1)).strftime('%Y-%m-%d') 
    enddate = (date + timedelta(days = 2)).strftime('%Y-%m-%d')         
    data = get_pricing([symbol],start_date= date1, end_date = todayDate, frequency='daily')
    df =  pd.DataFrame({"value": data.price.values.ravel()},index = data.major_axis.ravel())
    result = df.pct_change().dropna() 

    degree = {}
    for x in range(0,5):
        for y in range(0,5):
            try:
                arma = ARMA(result, (x,y)).fit()
                degree[str(x) +str(y)] = arma.aic

            except:
                continue

    dic= sorted(degree.iteritems(), key = lambda d:d[1])

    p = int(dic[0][0][0])
    q = int(dic[0][0][1])
    arma = ARMA(result, (p,q)).fit()
    predicts = arma.predict()
    exogx = np.array(range(1,4))
    predictofs = arma.predict(startdate,enddate, exogx)

The last line doesn't work and it produced an error

ValueError: Must provide freq argument if no data is supplied

I don't understand. Anyone had encountered the same issue?

Answer 1

I had the same issue it is because your index is missing the Freq argument. If you print data.index you will see that something like

DatetimeIndex(['2015-06-27', '2015-06-29', '2015-06-30', '2015-07-01', '2015-07-02', '2015-07-03', '2015-07-04', '2015-07-06', '2015-07-07', '2015-07-08', '2015-07-09', '2015-07-10', '2015-07-11', '2015-07-13', '2015-07-14', '2015-07-15', '2015-07-16', '2015-07-17', '2015-07-18', '2015-07-20', '2015-07-21', '2015-07-22', '2015-07-23', '2015-07-24', '2015-07-25', '2015-07-27', '2015-07-28', '2015-07-29', '2015-07-30', '2015-07-31'], dtype='datetime64[ns]', name=u'Date', freq=None)]

Note the 'Freq = None'

you can do something like :

data = Series(data.values, data.index)
data = data.asfreq('D')

You can also hard specify frequency by doing

data.index.freq = 'D'

Let me know if that helps a little.

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If that does not work you can simply use the integer to do the prediction and then fill the index manualy