[英]How to Create an Instance of a Class in runtime derived from ObservableCollection<T>?
How to Create an Instance of a Class in runtime derived from ObservableCollection 如何在派生自ObservableCollection的运行时中创建类的实例
The View Model and Model is given below :- C# Coding 视图模型和模型如下:-C#编码
public class Mobile
{
ObservableCollection<MobileModelInfo> SourceCollection = new ObservableCollection<MobileModelInfo>();
private void CreateObject(ObservableCollection<MobileModelInfo> Source)
{
/// Create an Object for MobileModelInfo Class in Runtime and add the Values
}
private ObservableCollection<MobileModelInfo> CostructMobileModel()
{
SourceCollection.Add(new MobileModelInfo { Name = "iPhone 4", Catagory = "Smart Phone", Year = "2011" });
SourceCollection.Add(new MobileModelInfo { Name = "S6", Catagory = "Ultra Smart Phone", Year = "2015" });
CreateObject(SourceCollection);
return SourceCollection;
}
}
public class MobileModelInfo
{
public string Name { get; set; }
public string Catagory { get; set; }
public string Year { get; set; }
}
From the example you've given you don't need a backing variable of ObservableCollection
type; 从给出的示例中,您不需要ObservableCollection
类型的后备变量; just inherit from it and your Mobile
class becomes an observable collection of MobileModelInfo
s. 只要继承自它,您的Mobile
类就成为MobileModelInfo
的可观察集合。 Note: it's much easier to bind to it using the below design pattern. 注意:使用以下设计模式将其绑定起来要容易得多。
public class Mobile : ObservableCollection<MobileModelInfo>
{
public Mobile()
{
Add(new MobileModelInfo { Name = "foo", Category = "boo", Year = 1988 } );
}
public Mobile GetList()
{
return this;
}
}
I Got the Solution for this issue. 我找到了这个问题的解决方案。 The Following is the C# Function it Create an Instance of a Class in runtime derived from ObservableCollection 以下是C#函数,它在运行时从ObservableCollection派生一个类的实例
private void CreateObject(ObservableCollection<MobileModelInfo> Source)
{
var gType = Source.GetType();
string collectionFullName = gType.FullName;
Type[] genericTypes = gType.GetGenericArguments();
string className = genericTypes[0].Name;
string classFullName = genericTypes[0].FullName;
// Get the type contained in the name string
Type type = Type.GetType(classFullName, true);
// create an instance of that type
object instance = Activator.CreateInstance(type);
// List of Propery for the above created instance of a dynamic class
List<PropertyInfo> oProperty = instance.GetType().GetProperties().ToList();
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.