Box2D中的ChainShape

Question

I recently began to learn libgdx and I am stuck at a problem with the CainShape of Box2D.

My first goal is to simply create a box with a ChainShape.

In order to achieve that, I added four Vector2 to an array and use them to create a loop.

The result is depending on the arrangement in the array either an hourglass shaped thing (top left is connected with bottom right and top right is connected with bottom left) or the error

Expression: b2DistanceSquared(v1, v2) > 0.005f * 0.005f

This is the code I used so far:

Vector2[] box = new Vector2[4];

    box[1] = new Vector2(0 -    bounds.getWidth() / 2 / Main.PPM, 0 -   bounds.getHeight() / 2 / Main.PPM);


    box[0] = new Vector2(       bounds.getWidth() / 2 / Main.PPM, 0 -   bounds.getHeight() / 2 / Main.PPM);


    box[2] = new Vector2(0 -    bounds.getWidth() / 2 / Main.PPM,       bounds.getHeight() / 2 / Main.PPM);


    box[3] = new Vector2(       bounds.getWidth() / 2 / Main.PPM,       bounds.getHeight() / 2 / Main.PPM);

    ChainShape chainShape = new ChainShape();
    chainShape.createLoop(box);

    fdef.shape = chainShape;
    fixture = body.createFixture(fdef);

I hope somebody can tell me what I am missing.
Thanks in advance!

Answer 1

Adjust the parameters you are passing and put in this code. This code will definitely run

ChainShape chain = new ChainShape();

createChain().Vec2[] vertices = new Vec2[2];
vertices[0] = box2d.coordPixelsToWorld(0,150); 
vertices[1] = box2d.coordPixelsToWorld(width,150);
chain.createChain(vertices, vertices.length);

FixtureDef fd = new FixtureDef();
fd.shape = chain; 
fd.density = 1;
fd.friction = 0.3;
fd.restitution = 0.5;
body.createFixture(fd);

Hope this answers the question if not please ask.