[英]Draw beautiful line programmatically using libGDX
In my libGDX project I have to draw such lines:在我的 libGDX 项目中,我必须绘制这样的线:
It may have various number of vertices.它可能有不同数量的顶点。 Currently I'm just adding it to stage as a texture with transparent background.
目前我只是将它作为具有透明背景的纹理添加到舞台上。 And if I have a lot of such lines, it takes quite a lot of space in atlases.
如果我有很多这样的行,它在地图集中需要相当多的空间。 So I want to draw these polygonal chains programmatically using libGDX.
所以我想使用 libGDX 以编程方式绘制这些多边形链。 I don't have much time and will to write my own libraries to achieve this, so I'm interested is some existing solutions.
我没有太多时间也不会编写自己的库来实现这一点,所以我对一些现有的解决方案感兴趣。 Two questions:
两个问题:
For this case, I think this might be the best way to do this, but take in mind that using OpenGL with Stage is not the easiest way to solve it...对于这种情况,我认为这可能是最好的方法,但请记住,将 OpenGL 与 Stage 结合使用并不是解决它的最简单方法......
On the other hand, an easier, but probably not that "beautiful" nor the faster way to solve it, could be using a TextureRegionDrawable, and scale, rotate and move for each point in your line path.另一方面,一种更简单但可能不是那么“漂亮”或更快的方法来解决它,可以使用 TextureRegionDrawable,并缩放、旋转和移动线路径中的每个点。
I wrote a little class, at least for a reference, it will need some polish, specially with corners.我写了一个小类,至少作为参考,它需要一些润色,特别是带有角落的。
public class LineDrawer extends Actor {
private Array<Vector2> path;
private float thickness;
private Image image;
public LineDrawer(Array<Vector2> path, float thickness, TextureRegionDrawable drawable) {
this.path = path;
this.thickness = thickness;
this.image = new Image(drawable);
this.image.setOrigin(Align.left);
}
@Override
public void draw(Batch batch, float parentAlpha) {
float dst, angle;
Vector2 pointA, pointB;
for (int i = 0; i < path.size - 1; i++) {
pointA = path.get(i);
pointB = path.get(i + 1);
dst = pointA.dst(pointB);
angle = MathUtils.atan2(pointB.y - pointA.y, pointB.x - pointA.x) * 180f / MathUtils.PI;
image.setSize(dst, thickness);
image.setPosition(pointA.x, pointA.y, Align.left);
image.setRotation(angle);
image.draw(batch, parentAlpha);
}
}
}
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