Python中的分段指数拟合

Question

I am trying to make a piecewise fitting as shown in fig.1:

Here is the code:

import numpy as np
from matplotlib import pyplot as plt
from scipy import optimize

def piecewise_linear(x, x0, y0, k1, k2):
    return np.piecewise(x, [x < x0], [lambda x: k1*np.power(x,k2), lambda x: y0])

x=np.arange(0.0,100.0,1.0)
y=piecewise_linear( x, 45.0, 2025.0, 1.0, 2.0)

popt , pcov = optimize.curve_fit(piecewise_linear, x, y)
tau = np.linspace(x[0], x[-1], 200)
perr = np.sqrt(np.diag(pcov))
print popt
print perr
print pcov
plt.plot(x, y, 'b+')
plt.plot(tau, piecewise_linear(tau, *popt),'r')
plt.loglog()
plt.show()
plt.close()

But this gave me fitting as fig. 2:

The parameter x0 was fixed at 1, no matter how I changed the data set.

I don't know what's wrong with my code, and how can I correct this?

Answer 1

Within your optimize.curve_fit() you need to specify some initial guess for the fitting using p0 = [] where you input your initial guesses into p0 , the documentation of which can be found here .

In terms of the example you have given, you already have the values of x0, y0, k1, k2 as you used them to calculate y , therefore just input these into your curve_fit :

def piecewise_linear(x, x0, y0, k1, k2):
    return np.piecewise(x, [x < x0], [lambda x: k1*np.power(x,k2), lambda x: y0])

x=np.arange(0.0,100.0,1.0)
y=piecewise_linear( x, 45.0, 2025.0, 1.0, 2.0)

#insert the initial guesses into curve_fit below using p0 = [...]
popt , pcov = optimize.curve_fit(piecewise_linear, x, y, p0=[45, 2000, 1, 2])
tau = np.linspace(x[0], x[-1], 200)
perr = np.sqrt(np.diag(pcov))

print (popt)
print (perr)
print (pcov)

plt.plot(x, y, 'b+')
plt.plot(tau, piecewise_linear(tau, *popt),'r')
plt.loglog()
plt.show()

This give the following graph: