[英]Storing scipy sparse matrix as HDF5
I want to compress and store a humongous Scipy matrix in HDF5 format. 我想以HDF5格式压缩并存储庞大的Scipy矩阵。 How do I do this?
我该怎么做呢? I've tried the below code:
我试过下面的代码:
a = csr_matrix((dat, (row, col)), shape=(947969, 36039))
f = h5py.File('foo.h5','w')
dset = f.create_dataset("init", data=a, dtype = int, compression='gzip')
I get errors like these, 我收到这样的错误,
TypeError: Scalar datasets don't support chunk/filter options
IOError: Can't prepare for writing data (No appropriate function for conversion path)
I can't convert it to numpy array as there will be memory overflow. 我无法将其转换为numpy数组,因为会发生内存溢出。 What is the best method?
最好的方法是什么?
A csr matrix stores it's values in 3 arrays. 一个csr矩阵将其值存储在3个数组中。 It is not an array or array subclass, so
h5py
cannot save it directly. 它不是数组或数组子类,因此
h5py
无法直接保存它。 The best you can do is save the attributes, and recreate the matrix on loading: 最好的办法是保存属性,并在加载时重新创建矩阵:
In [248]: M = sparse.random(5,10,.1, 'csr')
In [249]: M
Out[249]:
<5x10 sparse matrix of type '<class 'numpy.float64'>'
with 5 stored elements in Compressed Sparse Row format>
In [250]: M.data
Out[250]: array([ 0.91615298, 0.49907752, 0.09197862, 0.90442401, 0.93772772])
In [251]: M.indptr
Out[251]: array([0, 0, 1, 2, 3, 5], dtype=int32)
In [252]: M.indices
Out[252]: array([5, 7, 5, 2, 6], dtype=int32)
In [253]: M.data
Out[253]: array([ 0.91615298, 0.49907752, 0.09197862, 0.90442401, 0.93772772])
coo
format has data
, row
, col
attributes, basically the same as the (dat, (row, col))
you use to create your a
. coo
格式具有data
, row
和col
属性,基本上与用于创建a
的(dat, (row, col))
。
In [254]: M.tocoo().row
Out[254]: array([1, 2, 3, 4, 4], dtype=int32)
The new save_npz
function does: 新的
save_npz
函数可以:
arrays_dict = dict(format=matrix.format, shape=matrix.shape, data=matrix.data)
if matrix.format in ('csc', 'csr', 'bsr'):
arrays_dict.update(indices=matrix.indices, indptr=matrix.indptr)
...
elif matrix.format == 'coo':
arrays_dict.update(row=matrix.row, col=matrix.col)
...
np.savez(file, **arrays_dict)
In other words it collects the relevant attributes in a dictionary and uses savez
to create the zip archive. 换句话说,它在字典中收集相关属性,并使用
savez
创建zip存档。
The same sort of method could be used with a h5py
file. 相同的方法可以用于
h5py
文件。 More on that save_npz
in a recent SO question, with links to the source code. 最近的SO问题中有关
save_npz
更多信息,以及指向源代码的链接。
save_npz method missing from scipy.sparse scipy.sparse中缺少save_npz方法
See if you can get this working. 看看是否可以使它正常工作。 If you can create a
csr
matrix, you can recreate it from its attributes (or the coo
equivalents). 如果可以创建
csr
矩阵,则可以根据其属性(或coo
等效项)重新创建它。 I can make a working example if needed. 如果需要,我可以举一个工作的例子。
import numpy as np
import h5py
from scipy import sparse
M = sparse.random(10,10,.2, 'csr')
print(repr(M))
print(M.data)
print(M.indices)
print(M.indptr)
f = h5py.File('sparse.h5','w')
g = f.create_group('Mcsr')
g.create_dataset('data',data=M.data)
g.create_dataset('indptr',data=M.indptr)
g.create_dataset('indices',data=M.indices)
g.attrs['shape'] = M.shape
f.close()
f = h5py.File('sparse.h5','r')
print(list(f.keys()))
print(list(f['Mcsr'].keys()))
g2 = f['Mcsr']
print(g2.attrs['shape'])
M1 = sparse.csr_matrix((g2['data'][:],g2['indices'][:],
g2['indptr'][:]), g2.attrs['shape'])
print(repr(M1))
print(np.allclose(M1.A, M.A))
f.close()
producing 生产
1314:~/mypy$ python3 stack43390038.py
<10x10 sparse matrix of type '<class 'numpy.float64'>'
with 20 stored elements in Compressed Sparse Row format>
[ 0.13640389 0.92698959 .... 0.7762265 ]
[4 5 0 3 0 2 0 2 5 6 7 1 7 9 1 3 4 6 8 9]
[ 0 2 4 6 9 11 11 11 14 19 20]
['Mcsr']
['data', 'indices', 'indptr']
[10 10]
<10x10 sparse matrix of type '<class 'numpy.float64'>'
with 20 stored elements in Compressed Sparse Row format>
True
Mo = M.tocoo()
g = f.create_group('Mcoo')
g.create_dataset('data', data=Mo.data)
g.create_dataset('row', data=Mo.row)
g.create_dataset('col', data=Mo.col)
g.attrs['shape'] = Mo.shape
g2 = f['Mcoo']
M2 = sparse.coo_matrix((g2['data'], (g2['row'], g2['col'])),
g2.attrs['shape']) # don't need the [:]
# could also use sparse.csr_matrix or M2.tocsr()
You can use scipy.sparse.save_npz method 您可以使用scipy.sparse.save_npz方法
Alternatively consider using Pandas.SparseDataFrame , but be aware that this method is very slow (thanks to @hpaulj for testing and pointing it out ) 另外,也可以考虑使用Pandas.SparseDataFrame ,但是请注意,此方法非常慢 (感谢@hpaulj进行测试并将其指出 )
Demo: 演示:
generating sparse matrix and SparseDataFrame 生成稀疏矩阵和SparseDataFrame
In [55]: import pandas as pd
In [56]: from scipy.sparse import *
In [57]: m = csr_matrix((20, 10), dtype=np.int8)
In [58]: m
Out[58]:
<20x10 sparse matrix of type '<class 'numpy.int8'>'
with 0 stored elements in Compressed Sparse Row format>
In [59]: sdf = pd.SparseDataFrame([pd.SparseSeries(m[i].toarray().ravel(), fill_value=0)
...: for i in np.arange(m.shape[0])])
...:
In [61]: type(sdf)
Out[61]: pandas.sparse.frame.SparseDataFrame
In [62]: sdf.info()
<class 'pandas.sparse.frame.SparseDataFrame'>
RangeIndex: 20 entries, 0 to 19
Data columns (total 10 columns):
0 20 non-null int8
1 20 non-null int8
2 20 non-null int8
3 20 non-null int8
4 20 non-null int8
5 20 non-null int8
6 20 non-null int8
7 20 non-null int8
8 20 non-null int8
9 20 non-null int8
dtypes: int8(10)
memory usage: 280.0 bytes
saving SparseDataFrame to HDF file 将SparseDataFrame保存到HDF文件
In [64]: sdf.to_hdf('d:/temp/sparse_df.h5', 'sparse_df')
reading from HDF file 从HDF文件读取
In [65]: store = pd.HDFStore('d:/temp/sparse_df.h5')
In [66]: store
Out[66]:
<class 'pandas.io.pytables.HDFStore'>
File path: d:/temp/sparse_df.h5
/sparse_df sparse_frame
In [67]: x = store['sparse_df']
In [68]: type(x)
Out[68]: pandas.sparse.frame.SparseDataFrame
In [69]: x.info()
<class 'pandas.sparse.frame.SparseDataFrame'>
Int64Index: 20 entries, 0 to 19
Data columns (total 10 columns):
0 20 non-null int8
1 20 non-null int8
2 20 non-null int8
3 20 non-null int8
4 20 non-null int8
5 20 non-null int8
6 20 non-null int8
7 20 non-null int8
8 20 non-null int8
9 20 non-null int8
dtypes: int8(10)
memory usage: 360.0 bytes
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