绕过熊猫形状 (n,1) 到形状 (n,)

Question

I have a pandas dataframe and I want to convert it from (n,1) to shape (n,). probably I have to use squeeze but can't figure it out. squeeze documentation

by the way z['0']=z['0'].squeeze() didnt help.

Answer 1

You might be interested in .to_numpy() :

array = z['0'].to_numpy()

Answer 2

>>> s = pd.DataFrame({"col" : range(5)})
>>> s.shape
(5,1)

>>> s.col.to_numpy().shape
(5,)

Answer 3

z=z.squeeze() works the best and keeps the result dataframe. of course maybe its because I just had one columns, and didn't check it for more columns.