[英]Is possible to implement traits on generic types? (Rust)
I'm new to rust, and I want to implement the frequent math multiplication of a vector by a scalar: k * v<\/strong> =(k * v0,k * v1,k* v2..).我是 rust 新手,我想用一个标量实现向量的频繁数学乘法:k * v<\/strong> =(k * v0,k * v1,k* v2..)。 The code is the following:代码如下:
#[derive(Debug)]
struct V(Vec<i32>);
impl std::ops::Mul<V> for i32 {
type Output = V;
fn mul(self, v: V) -> V {
V(v.0.iter().map(|v| v * self).collect())
}
}
fn main() {
let v = V(vec![1,2]);
println!("{:?}", 3 * v);
}
In short, no.简而言之,没有。
You're running into the "orphan rule".你遇到了“孤儿规则”。 The basic idea is that if you want to implement a trait X<\/code> , on a struct\/enum\/union
Y<\/code> , at least one<\/em> of those must be defined in the current crate.
基本思想是,如果要在 struct\/enum\/union
Y<\/code>上实现 trait
X<\/code> ,至少<\/em>必须在当前 crate 中定义其中之一。
This is somewhat restrictive at times, but it is a product of Rusts "coherence rules".这有时有些限制,但它是 Rust 的“连贯性规则”的产物。 In general, every combination of traits and types must have at most 1 implementation.一般来说,每个特征和类型的组合最多只能有 1 个实现。 So the following code is not valid:所以下面的代码是无效的:
struct Wrapper<T>(T);
trait Print {
fn print(&self);
}
impl Print for Wrapper<i32> {
fn print(&self) {
println!("a very special int: {}", self);
}
}
impl<T: Display> Print for Wrapper<T> {
fn print(&self) {
print!("a normal type: {}", self);
}
}
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