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从24位WAV PCM格式转换为float的更快方法?

[英]Faster way to convert from 24 bit wav pcm format to float?

I need to read data in from a wav file in 24 bit pcm format, and convert to float. 我需要从24位pcm格式的wav文件中读取数据,然后转换为float。 I'm using Python 2.7.2. 我正在使用Python 2.7.2。

The wave package reads the data in as a string, so what I've tried is: wave包以字符串形式读取数据,因此我尝试了以下操作:

import wave
import numpy as np
import array
import struct

f = wave.open('filename.wav')
# read in entire wav file
wdata = f.readframes(nFrames) 
f.close()

# unpack into signed integers and convert to float      
data = array.array('f')
for i in range(0,nFrames*3,3):
    data.append(float(struct.unpack('<i', '\x00'+ wdata[i:i+3])[0]))

# normalize sample values
data = np.array(data)
data = data / 0x800000

This is quite a bit faster than my earlier approaches, but still quite slow. 这比我以前的方法要快很多,但仍然很慢。 Can anyone suggest a more efficient method? 谁能建议一种更有效的方法?

This seems to be quite fast, it handles 24-bit values, and it does the normalization: 这似乎相当快,它处理24位值,并进行规范化:

from scikits.audiolab import Sndfile
import numpy as np

f = Sndfile(fname, 'r')
data = np.array(f.read_frames(f.nframes), dtype=np.float64)
f.close()
return data

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