Java Regex匹配之前和之后的所有内容

Question

I have strings of the form: something~#~something.

Essentially I am using ~#~ as a delimiter, but I would like to only split the first element from the rest of the elements.

For instance, if I had the following string: What~#~AGreat~#~Day

I would like my first match to be "What" and my second match to be "AGreat~#~Day.

The actual strings I'm working with look like this: A1~#~@NP->_A1 So they're not limited to alphanumeric characters. Can anyone help? I tried looking around for a similar problem but I can't seem to get it working.

Thanks!

Answer 1

String first = input.substring(0, input.indexOf("~#~"));
String second = input.substring(input.indexOf("~#~") + 3, input.length());

Output:

first:  What
second: AGreat~#~Day

Answer 2

You could also use split(String regex, int limit) method. For example this code

public class Test {
    public static void main(String[] args) {
        String s = "abc.bcd.cde";
        System.out.println(Arrays.toString(s.split("\\.", 2)));
    }
}

produces the following output:

[abc, bcd.cde]