Recovering the string split by string.split() in Java

Question

I have a string " I love A. I hate B ". If I split it by using

 string.split("\\p{Punct}") 

I will get two strings where string1 will be " I love A " and string2 will be " I hate B ". Please note that in place of " . " I may also have any of the other punctuation characters. How can I recover the exact string as it was before the splitting operation with the correct punctuation character.

Answer 1

保持对字符串的引用 - 如果你有任何一点点，你就无法猜出你以前有过什么

Answer 2

If you split using the following regular expression (using a zero-width look-behind assertion ):

(?<=\p{Punct})

It will not actually consume the punctuation character, but just check that there is a punctuation character directly before the split point. As a result, the punctuation characters are left in the final strings:

String s = "I love A. I hate B.";
String res[] = s.split("(?<=\\p{Punct})");
System.out.println(Arrays.toString(res));

Result:

[I love A.,  I hate B.]

Now you could concatenate the elements of the array back together to recover the original string.

Demo: http://ideone.com/0umjkZ

Answer 3

You can use StringTokenizer and manage the elements with the method nextElement().

Sample.

String str = "I love A. I hate B";

StringTokenizer st = new StringTokenizer(str,".");

String beforeElement;
String otherElement;

while (st.hasMoreElements()){

    beforeElement=st.nextElement();

     if(st.hasMoreElements()){

       otherElement=st.nextElement();

    }

}