Mysql: insert if row doesn't exist, else update.. is there a simpler command?

Question

Learning Mysql and having piles of questions...

I can achieve desired effect by simple:

$mysqli->query("INSERT results SET user_id = '".$user_data[0]['user_id']."', logo_id = '".$mysqli->real_escape_string($_GET['logo_id'])."'");
$mysqli->query("UPDATE results SET result_tries = result_tries +1 WHERE logo_id = '".$mysqli->real_escape_string($_GET['logo_id'])."' AND user_id = '".$user_data[0]['user_id']."'");

I've DB unique check on the table, so that logo_id and user_id should be unique. So if row exists first query fails, and the second update is executed..., But this feels kind of hack... Is there a better way to do this?

Answer 1

Try

$user_id = $user_data[0]['user_id'];
$logo_id = $mysqli->real_escape_string($_GET['logo_id']);

$sql = "INSERT INTO results (user_id, logo_id, result_tries) 
        VALUES ('$user_id', '$logo_id', 0)
            ON DUPLICATE KEY UPDATE result_tries = result_tries + 1";

$mysqli->query($sql);

Answer 2

In my case:

INSERT INTO assignment_status (user, assignment, status, note) VALUES (4, 7, 2, "My special note.")
ON DUPLICATE KEY UPDATE status=2, note="My special note."

Note that my primary key consists of 2 columns - user and assignment IDs...