I have such query:
SELECT c.name, i.name FROM inv_invoice_items c
LEFT OUTER JOIN inv_invoice_items i ON i.name = c.name
WHERE c.id_invoice = 2108 AND i.id_invoice = (SELECT id_invoice FROM inv_invoices WHERE id = 2108)
For this query I have such result:
name | name
-------------
pen | pen
but for select without join:
SELECT c.name FROM inv_invoice_items c
WHERE c.id_invoice = 2108
the result is:
name
------
pen
pencil
and second query:
SELECT i.name FROM inv_invoice_items i
WHERE i.id_invoice = (SELECT id_invoice FROM inv_invoices WHERE id = 2108)
gives result:
name
------
pen
I would expect for my first join query result:
name | name
---------------
pen | pen
pencil | NULL
How to achieve such result? I thought that way should work LEFT OUTER JOIN. Thanks for any suggestions in advance.
Ps. I need to catch differences in invoice items of corrective and corrected (related ) invoice.
Some sample data:
create table inv_invoices (id bigint, id_invoice bigint, primary key(id));
create table inv_invoice_items (id bigint, id_invoice bigint NOT NULL, name character varying(100) NOT NULL, primary key (id));
insert into inv_invoices values (2105, NULL), (2106, NULL), (2107, NULL), (2108, 2106);
insert into inv_invoice_items values (1000, 2105, 'pen'), (1001, 2105, 'pencil'), (1002,2106, 'pen'), (1003, 2107, 'rubber'),
(1004, 2107, 'pencil'), (1005, 2108, 'pen'), (1006, 2108, 'pencil');
Try this instead:
SELECT DISTINCT c.name, i.name FROM inv_invoice_items AS c LEFT OUTER JOIN inv_invoice_items AS i ON i.name = c.name AND c.id_invoice = 2108 LEFT OUTER JOIN inv_invoices AS i2 ON i.id_invoice = i2.id_invoice AND i2.id = 2108;
Try this:
SELECT
t.name AS name1,
v.name AS name2
FROM
(
SELECT c.name
FROM inv_invoice_items c
WHERE c.id_invoice = 2108
) AS t
LEFT JOIN
(
SELECT i.name
FROM inv_invoice_items i
WHERE i.id_invoice = (SELECT id_invoice
FROM inv_invoices
WHERE id = 2108)
) AS v ON t.name = v.name;
This will give you:
| NAME1 | NAME2 |
-------------------
| pen | pen |
| pencil | (null) |
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